Answer: Equilibrium concentration of
Equilibrium concentration of
Explanation:
Initial moles of =
Volume of container = 1.00 L
Initial concentration of
Initial concentration of B=
Initial concentration of
Equilibrium concentration of
The given balanced equilibrium reaction is,
Initial :
At eqm:
we are given :
Equilibrium concentration of
Equilibrium concentration of
If this is a true/false question then it is true.
The balanced equation for the reaction between Na and H₂SO₄ is as follows;
2Na + H₂SO₄ ---> Na₂SO₄ + H₂
Stoichiometry of Na to H₂SO₄ is 2:1
the molar concentration of H₂SO₄ is 6.0 M
This means that in 1 L of H₂SO₄ - there are 6.0 mol of H₂SO₄
Therefore in 750 mL -
Number of H₂SO₄ moles reacted - 4.5 mol
According to stoichiometry,
1 mol of H₂SO₄ reacts with 2 mol of Na
Therefore 4.5 mol reacts with 2x4.5= 9 mol of Na
Mass of Na reacted - 9 mol x 23 g/mol = 207 g of Na is required
"Melting Point" - The Required <span>amount of heat to melt a substance</span>
Answer:
40 moles of Na2CO3 has the mass of = 105.98×40 = 4239.2 grams = 4.2392 kilograms.
Explanation: