Answer:
The solution of the given initial value problems in explicit form is 
and the solutions are defined for all real numbers.
Step-by-step explanation:
The given differential equation is
It can be written as
Use variable separable method to solve this differential equation.
Integrate both the sides.
![[\because \int x^n=\frac{x^{n+1}}{n+1}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cint%20x%5En%3D%5Cfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%5D)
... (1)
It is given that y(1) = -2. Substitute x=1 and y=-2 to find the value of C.
The value of C is -2. Substitute C=-2 in equation (1).
Therefore the solution of the given initial value problems in explicit form is .
The solution is quadratic function, so it is defined for all real values.
Therefore the solutions are defined for all real numbers.
A: 11% x 67530 = $7428.30
B: 8% x 85740 = $6859.20
Person A made more commission
Answer:
1) Is more representative
Step-by-step explanation:
The problem with his selection is that maybe there are few students participating in certain sport and those students maybe do quite more excercise than the rest (or quite less). This will modify the results because the sample he selected is biased. This problem wont be solved by method 3 or 4, because he is still selecting students that may modify heavily the results with a high probability
This problem will also appear if he choose a sample by class. Maybe, in a class there are quite few students, and selecting from class will make those students appear quite more often than, lets say, a 7th grade student selected at random, therefore the selection is biased in this case as well.
If he has a list with all seventh grade students, each student is equallly likely to be selected and as a consequence, the the results wont be biased. Approach 1 is the best one.
