Use substitution
From second equation:-
x = 13 - 5y, Substitute for x in the first eqaution:
(13 - 5y)^2 + y^2 = 13
169 -130y + 25y^2 + y^2 - 13 = 0
26y^2 - 130y + 156 = 0
26(y^2 - 5y + 6) = 0
26(y - 3)(y - 2) = 0
y = 2 , y = 3
From the second equation when y = 2, x = 13 - 5(2) = 3
and when y = 3, x = 13 - 5(3) = -2
So the solution is [3, 2} and {-2, 3}
Answer:
1.8 m
Step-by-step explanation:
h(T)=-9.8T^2+20T+1
just replace the T with 2
h=-9.8(2^2)+20(2)+1
-9.8×4+40+1=1.8m
1.8m
9s, 3s+6s, -1s+10s any works
Answer:
y = 2/3x + 5/3
Step-by-step explanation:
The slope of the line is ...
slope = (change in y)/(change in x) = (3-1)/(2-(-1)) = 2/3
Then the point-slope form of the desired line can be written ...
y = m(x -h) +k . . . . . slope m through point (h, k)
y = 2/3(x +1) +1 . . . . slope 2/3 through point (-1, 1)
y = 2/3x + 5/3 . . . . . . simplify to slope-intercept form