1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly [62]
3 years ago
15

The holding period of property acquired by gift may begin on:

Mathematics
2 answers:
maw [93]3 years ago
6 0

Answer:

Step-by-step explanation:

lianna [129]3 years ago
3 0

Answer:

The answer is C. Either the date the property was acquired by the donor or the date of the gift.

Step-by-step explanation:

The donor's holding time is included in the holding period connected with the gain basis rule. The loss basis rule's holding period begins on the day of the donation.

You might be interested in
What is the absolute of -32
luda_lava [24]
The answer is 32 because on a number line it is the distance between the number and zero.
8 0
3 years ago
Read 2 more answers
PLS HELP ME WITH MY GEOMETRY I WILL GIVE BRAINLYIST IF IT GIVES ME THE OPION
Vika [28.1K]

Answer:

the 3rd one is yes the rest are no

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Choose the equation of a circle with radius 6 and center (2, -3).
Rufina [12.5K]

Answer:  (x-2)^2 + (y+3)^2 = 36\\\\

Work Shown:

(x-h)^2 + (y-k)^2 = r^2\\\\(x-2)^2 + (y-(-3))^2 = 6^2\\\\(x-2)^2 + (y+3)^2 = 36\\\\

Note that (h,k) = (2,-3) is the center and r = 6 is the radius. The last line is not expanded out using the FOIL rule because its common practice to leave it in (x-h)^2 + (y-k)^2 = r^2\\\\ form. This form allows the reader to quickly determine the center and radius (rather than have to do a lot of algebraic steps before hand).

3 0
2 years ago
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
Katena32 [7]

Answer:

(a) The fraction of the calls last between 4.50 and 5.30 minutes is 0.3729.

(b) The fraction of the calls last more than 5.30 minutes is 0.1271.

(c) The fraction of the calls last between 5.30 and 6.00 minutes is 0.1109.

(d) The fraction of the calls last between 4.00 and 6.00 minutes is 0.745.

(e) The time is 5.65 minutes.

Step-by-step explanation:

We are given that the mean length of time per call was 4.5 minutes and the standard deviation was 0.70 minutes.

Let X = <u><em>the length of the calls, in minutes.</em></u>

So, X ~ Normal(\mu=4.5,\sigma^{2} =0.70^{2})

The z-score probability distribution for the normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean time = 4.5 minutes

           \sigma = standard deviation = 0.7 minutes

(a) The fraction of the calls last between 4.50 and 5.30 minutes is given by = P(4.50 min < X < 5.30 min) = P(X < 5.30 min) - P(X \leq 4.50 min)

    P(X < 5.30 min) = P( \frac{X-\mu}{\sigma} < \frac{5.30-4.5}{0.7} ) = P(Z < 1.14) = 0.8729

    P(X \leq 4.50 min) = P( \frac{X-\mu}{\sigma} \leq \frac{4.5-4.5}{0.7} ) = P(Z \leq 0) = 0.50

The above probability is calculated by looking at the value of x = 1.14 and x = 0 in the z table which has an area of 0.8729 and 0.50 respectively.

Therefore, P(4.50 min < X < 5.30 min) = 0.8729 - 0.50 = <u>0.3729</u>.

(b) The fraction of the calls last more than 5.30 minutes is given by = P(X > 5.30 minutes)

    P(X > 5.30 min) = P( \frac{X-\mu}{\sigma} > \frac{5.30-4.5}{0.7} ) = P(Z > 1.14) = 1 - P(Z \leq 1.14)

                                                              = 1 - 0.8729 = <u>0.1271</u>

The above probability is calculated by looking at the value of x = 1.14 in the z table which has an area of 0.8729.

(c) The fraction of the calls last between 5.30 and 6.00 minutes is given by = P(5.30 min < X < 6.00 min) = P(X < 6.00 min) - P(X \leq 5.30 min)

    P(X < 6.00 min) = P( \frac{X-\mu}{\sigma} < \frac{6-4.5}{0.7} ) = P(Z < 2.14) = 0.9838

    P(X \leq 5.30 min) = P( \frac{X-\mu}{\sigma} \leq \frac{5.30-4.5}{0.7} ) = P(Z \leq 1.14) = 0.8729

The above probability is calculated by looking at the value of x = 2.14 and x = 1.14 in the z table which has an area of 0.9838 and 0.8729 respectively.

Therefore, P(4.50 min < X < 5.30 min) = 0.9838 - 0.8729 = <u>0.1109</u>.

(d) The fraction of the calls last between 4.00 and 6.00 minutes is given by = P(4.00 min < X < 6.00 min) = P(X < 6.00 min) - P(X \leq 4.00 min)

    P(X < 6.00 min) = P( \frac{X-\mu}{\sigma} < \frac{6-4.5}{0.7} ) = P(Z < 2.14) = 0.9838

    P(X \leq 4.00 min) = P( \frac{X-\mu}{\sigma} \leq \frac{4.0-4.5}{0.7} ) = P(Z \leq -0.71) = 1 - P(Z < 0.71)

                                                              = 1 - 0.7612 = 0.2388

The above probability is calculated by looking at the value of x = 2.14 and x = 0.71 in the z table which has an area of 0.9838 and 0.7612 respectively.

Therefore, P(4.50 min < X < 5.30 min) = 0.9838 - 0.2388 = <u>0.745</u>.

(e) We have to find the time that represents the length of the longest (in duration) 5 percent of the calls, that means;

            P(X > x) = 0.05            {where x is the required time}

            P( \frac{X-\mu}{\sigma} > \frac{x-4.5}{0.7} ) = 0.05

            P(Z > \frac{x-4.5}{0.7} ) = 0.05

Now, in the z table the critical value of x which represents the top 5% of the area is given as 1.645, that is;

                      \frac{x-4.5}{0.7}=1.645

                      {x-4.5}{}=1.645 \times 0.7

                       x = 4.5 + 1.15 = 5.65 minutes.

SO, the time is 5.65 minutes.

7 0
3 years ago
5 pounds 80 cents $1.40 per pound
tensa zangetsu [6.8K]

What’s your question?

6 0
3 years ago
Other questions:
  • Solve the equation using the Zero-Product Property.
    9·1 answer
  • There are 365 days in a year and 24 hours in a day. How Many hours are in 4 years?
    5·2 answers
  • Ellie has 4 quarters for every 5 pennies in her change purse. How many pennies would she have if she has 16 quarters?
    13·2 answers
  • The length of a rectangle is six times its width.
    15·1 answer
  • Can someone please help me graph this I really need help and I’m really confused !!
    10·1 answer
  • How do I do this problem? Can I get a explanation. The 2 options are yes and no.
    9·1 answer
  • Someone help plz no web sights and plz make sure it’s right :) if it is will mark brainiest
    15·2 answers
  • Consider function h. Complete the statements describing the y-values of function h.
    8·1 answer
  • Write the equation of the line in standard form.
    9·1 answer
  • Ashley will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $44 and costs an a
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!