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Ksju [112]
3 years ago
10

Is -x equal to -1x?

Mathematics
2 answers:
Lapatulllka [165]3 years ago
8 0

Answer:

Yes

Step-by-step explanation:

-1x is a short notation for -1 * x. the "-" can stand for -1

So it would be (-1) * (1) * x

-x is also -1 * x

By the identity property of multiplication, a number x 1 remains the same number.

So it would be -1 * x, which is the same as -1 * x, so they're equal.


LUCKY_DIMON [66]3 years ago
3 0

Answer: yes!


Step-by-step explanation:

Any variable that doesn’t have an integer in front of it, it is implied that it is a (1). Ex: x or -x is the same as 1x or -1x

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If (-1,4) and (3,-2) are end points of diameter of the circle, then the equation of the circle is
Volgvan

Answer:

If you've more doubts you can ask :)

Step-by-step explanation:

If the centre of a circle is (a, b) and radius r, then the equation of the circle is :

(x - x)^2 + (y-b)^2 = r^2

<em><u>First we will find the centre, (a , b): </u></em>

<em><u /></em>a = \frac{3+(-1)}{2} = \frac{2}{2} = 1\\\\b = \frac{-2 + 4}{2} = \frac{2}{2} = 1<em><u /></em>

<em><u>Find radius:</u></em>

Radius, r = \frac{Diameter}{2}

Diameter is the distance between (-1, 4) and (3, -2)

diameter = \sqrt{(x_2 - x_1)^2 +(y_2-y_1)^2} \\\\

             = \sqrt{(3-(-1)^2 + (-2-4)^2} \\\\=\sqrt{16 + 36}\\\\=\sqrt{52}\\\\=\sqrt{4 \times 13}\\\\=2\sqrt{13}    \ units

Therefore , r = \frac{2 \times \sqrt{13} }{2} = \sqrt{13}  \ units

<em><u>Equation of the circle is :  </u></em>

                                 (x - 1)^2 +(y-1)^2 = 13<em><u></u></em>

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How many miles can you go on 28 gallons
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6 0
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At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
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The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

y^2 – 2y – 1 = 0

Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
4 years ago
Cho tam giác ABC vuông tại A &lt; góc B=a chứng minh: a) 1+<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7D" id="TexFormula1" tit
dimaraw [331]
<h3><u>L</u><u>H</u><u>S</u><u>:</u><u>-</u></h3>

\\ \sf\longmapsto 1+tan^2A

\boxed{\sf tanA=\dfrac{sinA}{cosA}}

\\ \sf\longmapsto 1+\dfrac{sin^2A}{cos^2A}

\\ \sf\longmapsto \dfrac{cos^2A+sin^2A}{cos^2A}

\boxed{\sf cos^2A+sin^2A=1}

\\ \sf\longmapsto \dfrac{1}{cos^2A}

\\ \sf\longmapsto \dfrac{1}{1-sin^2A}

\\ \sf\longmapsto \dfrac{1}{1}-\dfrac{1}{sin^2A}

\\ \sf\longmapsto \dfrac{1}{sin^2A}

Hence verified

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