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RSB [31]
3 years ago
14

The measure of angle θ is 3pi/2 . The measure of its reference angle is /, and tan θ is .

Mathematics
1 answer:
Sphinxa [80]3 years ago
8 0

Answer:

Reference angle: \frac{\pi}{2}

tan(\theta)=tan(\frac{3\pi}{2}) is not defined.

Step-by-step explanation:

The angle \theta goes from the positive x-axis to the negative y-axis.

Therefore the reference angle can be calculated as following:

\frac{3\pi}{2}-\pi=\frac{\pi}{2}

 We know that tan(\theta)is:

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

If \theta=\frac{3\pi}{2} then cos(\frac{3\pi}{2})=0, therefore tan(\frac{3\pi}{2}) is not defined, because the division by 0 is not defined.

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Which step is the same in the construction of parallel lines and the construction of a perpendicular line through a point on the
madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

6 0
3 years ago
Read 2 more answers
Write .008% as a decimal
lions [1.4K]
0.008%=0.008/100=0.00008
5 0
3 years ago
Radioactive Decay Beginning with 16 grams of a radioactive element whose half -life is 30 years ,the mass y(in grams) remaining
Flura [38]

Answer:

the equation should be corrected to fit the data of the problem.  With the corrected equation a mass of 0.5 grams remains after 150 years

Step-by-step explanation:

for the mass y( in grams)

y=23* (1/2)^(t/45), t ≥ 0.

the initial mass is at t=0 , then

y= 23 grams  → should be 16 grams

half-life from the equation = 45 years → should be 30 years

the correct equation should be

y=16*(1/2)^(t/30), t ≥ 0

then after 150 years  → t= 150

y=16*(1/2)^(150/30)= 16*(1/2)^5 = 16/32 = 0.5 grams

then a mass of 0.5 grams remains after 150 years

5 0
3 years ago
A number has the digits 9
N76 [4]

Answer:

97

Step-by-step explanation:

There is no explanation

3 0
3 years ago
Read 2 more answers
Can someone help me with this problem??
Crank

Answer:

V = 33.49

Step-By-Step Explanation:

V = 4/3πr³

V = 4/3×π×2³

V = 4/3×π×8

V = 4/3×25.12

V = 33.49333...

Shortened

V = 33.49

4 0
3 years ago
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