Ummm this is question 18 not 1r don’t you want help on 14¿¿
Mostly collect like terms
use associative property which is
(a+b)+c=a+(b+c)
and remember that:
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
you can only add like terms( like terms are terms that are same name like x or y are differnt, and like terms have same power exg x^2 and x^3 and x^1/2 and such
so first one
3b+11c-4c-c
since they are all c except for the first one term, just assign a number for each so it simplifies to c times(11-1)+b(3-4)=c(10-1b=10c-b or
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
second one9a-1+8c-8a+c
group like terms
(9a-8a)+(8c+c)-1=(a)+(9c)-1=a+9c-1
12c+5a+7-13c+4a
group like terms(12c-13c)+(5a+4a)+7
add like terms
-c+9a+7
the solution is 9a-c+7
-15-6c+3b-6c+9-2b
group like terms
(-15+9)+(-6c-6c)+(3b-2b)
-6+(-12c)+b=b-6-12c
the answers are:
10c-b
a+9c-1
9a-c+7
b-12c-6
Answer:
Slope: 6
y-intercept: −3
Step-by-step explanation:
She made her first mistake in step 2
-2x+5 =-11
add 5 to each side
-2x-5+5 = -11+5
-2x = -6 (not -16)
divide by -2
-2x/-2 = -6/-2
x = 3
She added 5 to 11 and got 16 and made it negative instead of subtracting 5 from 11 and making it negative
Answer:
73 trees can be planted on equal distance and 11 trees would be left over.
Step-by-step explanation:
Given:
Number of trees to be planted = 4245
Number of miles of highway = 58
We need to find Number of trees can be planted in equal distance and number of trees to be left over.
Solution:
Now we can say that;
Number of trees can be planted in equal distance can be calculated by dividing Number of trees to be planted by Number of miles of highway.
framing in equation form we get;
Number of trees can be planted in equal distance = 
So we can say that.
73 trees can be planted on equal distance and 11 trees would be left over.
