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Natali [406]
3 years ago
13

Last question! I might have like 4 different ones.

Mathematics
1 answer:
Ksju [112]3 years ago
4 0
Y^-1 • y = 0

x^-6/ x^2= x^-8

x^-8 = 1/ x^8

1/x^8
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{x^2+6x-27/x^2-9x+18<br> how to solve step by step
Alika [10]

Answer:

Step-by-step explanation:

Step by Step Solution:

More Icon

STEP

1

:

5

Simplify ———————

x2 - 81

Trying to factor as a Difference of Squares:

1.1 Factoring: x2 - 81

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 81 is the square of 9

Check : x2 is the square of x1

Factorization is : (x + 9) • (x - 9)

Equation at the end of step

1

:

(((x2)-18x)+81) 5

———————————————•———————————

(((x2)-6x)-27) (x+9)•(x-9)

STEP

2

:

x2 - 18x + 81

Simplify —————————————

x2 - 6x - 27

Trying to factor by splitting the middle term

2.1 Factoring x2 - 18x + 81

The first term is, x2 its coefficient is 1 .

The middle term is, -18x its coefficient is -18 .

The last term, "the constant", is +81

Step-1 : Multiply the coefficient of the first term by the constant 1 • 81 = 81

Step-2 : Find two factors of 81 whose sum equals the coefficient of the middle term, which is -18 .

-81 + -1 = -82

-27 + -3 = -30

-9 + -9 = -18 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -9

x2 - 9x - 9x - 81

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-9)

Add up the last 2 terms, pulling out common factors :

9 • (x-9)

Step-5 : Add up the four terms of step 4 :

(x-9) • (x-9)

Which is the desired factorization

Trying to factor by splitting the middle term

2.2 Factoring x2-6x-27

The first term is, x2 its coefficient is 1 .

The middle term is, -6x its coefficient is -6 .

The last term, "the constant", is -27

Step-1 : Multiply the coefficient of the first term by the constant 1 • -27 = -27

Step-2 : Find two factors of -27 whose sum equals the coefficient of the middle term, which is -6 .

-27 + 1 = -26

-9 + 3 = -6 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and 3

x2 - 9x + 3x - 27

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-9)

Add up the last 2 terms, pulling out common factors :

3 • (x-9)

Step-5 : Add up the four terms of step 4 :

(x+3) • (x-9)

Which is the desired factorization

Canceling Out :

2.3 Cancel out (x-9) which appears on both sides of the fraction line.

Equation at the end of step

2

:

(x - 9) 5

——————— • —————————————————

x + 3 (x + 9) • (x - 9)

STEP

3

:

Canceling Out

3.1 Cancel out (x-9) which appears on both sides of the fraction line.

Final result :

5

—————————————————

(x + 3) • (x + 9)

5 0
2 years ago
Calculate A^2, given A=[tex]Given A=[−3 4/-2 0}
MatroZZZ [7]

Answer:

\large\boxed{A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right] }

Step-by-step explanation:

A=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] \cdot\left[\begin{array}{ccc}-3&4\\-2&0\end{array}\right] =\left[\begin{array}{ccc}(-3)(-3)+(4)(-2)&(-3)(4)+(4)(0)\\(-2)(-3)+(0)(-2)&(-2)(4)+(0)(0)\end{array}\right]\\\\A^2=\left[\begin{array}{ccc}1&-12\\6&-8\end{array}\right]

8 0
3 years ago
Im giving free brain list just answer this question . what is 9.62 x 0.38
Sphinxa [80]

Answer:

3.6556

Step-by-step explanation:

Multiply both, can i get brainliest?

5 0
2 years ago
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nirvana33 [79]
An angle of 200 degrees in an obtuse angle.
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3 years ago
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PROVE THAT TWO TRIANGLES ARE CONGRUENT USING THE SAS CONGRUENCE CRITERIA PLEASEEEEE I NEED ASAP DUE IN 15 MINS PLEEEEASE​
Klio2033 [76]

Answer:

Side-Angle-Side is a rule used to prove whether a given set of triangles are congruent. If two sides and the included angle of one triangle are equal to two sides and included angle of another triangle, then the triangles are congruent.

Step-by-step explanation:

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3 years ago
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