Find the particular solution to y " = 2sin(x) given the general solution y = −2sin(x) + Ax + B and the initial conditions y of p
i over 2 equals 0 and y prime of pi over 2 equals negative 2.
−2sin(x) + 2
−2sin(x) − 2x + π + 2
−2sin(x) − 2x + 2π
−2sin(x) − 2x + π
−2sin(x) + 2
−2sin(x) − 2x + π + 2
−2sin(x) − 2x + 2π
−2sin(x) − 2x + π
1 answer:
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Answer:
From top to bottom:
Step-by-step explanation:
We are given the piecewise function:
Row 1:
We want to find g(-2).
Since -2 is less than (or equal to) 2, we will use the first equation. Thus:
Row 2:
Likewise, 0 is less than or equal to 2. We will continue to use the first equation:
Row 3:
2 is not less than 2 but it is equal to 2. So we will continue to use the first equation:
Row 4 and 5:
Both 4 and 6 are greater than 2. Thus, we will use the second equation. Therefore:
Using pythagoras theorem,
a^2 + b^2 =c^2
11^2 + 11^2 = c^2
c^2=242
c=
c= 15.556
c=15.6