(4a^2b-3ab^2+2ab+5)+(2ab^2b+3ab^2-7ab)

What is the largest number you can form from the numbers $2,5,8,9,10$ and the operations $\times,+,+,-$, and exactly one pair of

Levart [38]

Answer:

The largest number is 218.

Step-by-step explanation:

The given numbers are 2,5,8,9,10, given operations are ×,+,+,- and exactly one pair of parentheses.

We need to find the largest number which can be form by using given information.

We know that multiplication of two lager numbers is greater than their addition.

We need to multiply 10 and sum of 9,8,5. To get the largest number we have subtract the smallest number.

So, the largest possible number is defined by the expression

$10\times (9+8+5)-2$

$10\times (22)-2$

$220-2$

$218$

Therefore, the largest number is 218.

6 0

3 years ago

Is number 19 correct

olganol [36]

Yes it is. Hope it helps.:)

8 0

3 years ago

Read 2 more answers

Hunter had 3⁄8 of a pizza. He gave 2⁄3 of the pizza to his friend Taylor. What fraction of the whole pizza did Taylor get?

Nikitich [7]

Answer:

1/4

Step-by-step explanation:

3/8 * 2/3 = 6/24 = 1/4

AAAAAAAA .... whole pizza

AAA ... Hunter had

AA ... tylor get

4 0

3 years ago

Use the ray tool to graph g(x)={2x, x≥3; −13x+7, x≤3

klio [65]

Answer:

See graph

Step-by-step explanation:

We want to graph the piece-wise function,

$g(x)=\left \{ {{2x,x\geq 3} \atop {-\frac{1}{3}x+7,x\le3}} \right.$

The two functions has a common point which is

$(3,6)$ .

Plot this point and one additional point on each line say;

$(-6,9)$ and $(5,10)$ .

Click the ray tool and click the common point first and then click the second point to draw the first line.

Repeat the same process to draw the second line.

This will give you the graph that is similar to the one in the attachment.

6 0

3 years ago

Read 2 more answers

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.

steposvetlana [31]

An arithmetic sequence with first term a, and a common distance d si as follows:

m, m+d, m+2d, m+3d, ...

(for example: 3, 8, 13, 18 .... m=3, d=5)

let $\displaystyle{ a_n$ be the n'th term of the arithmeti sequence

m, m+d, m+2d, m+3d, ...

then

$a_1=m\\\\a_2=m+d\\\\a_3=m+2d\\\\a_4=m+3d \\\\ .\\\\.$

so it is clear that the n'th term, si given by :

$a(n)=m+(n-1)d$

compare the rule we found with the given rule A(n)=-3+(n-1)(-2.2)

it is clear that m=-3, and d=-2.2,

so the sequence

m, m+d, m+2d, m+3d, ...

becomes:

-3, -3-2.2, -3-2*2.2, -3-3*2.2, ....

so

-3, -5.2, -7.4, -9.6

the first term is -3, the fourth term is -9.6, the 10th term can be found by plugging in n=10 in the formula:

<span>A(10) = –3 + (10 – 1)(–2.2)=-3+9(-2.2)=-3-19.8=-22.8

remark, we could have use the formula directly and solve for A(1), A(4) and A(10),

but with the explanations we see how we find derive the formula, and makes it easier to derive, even when we don't remember it properly.

Answer:

1st term=-3

2nd term=-9.6

10th term = -22.8</span>

5 0

3 years ago