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elixir [45]
3 years ago
5

(4a^2b-3ab^2+2ab+5)+(2ab^2b+3ab^2-7ab)

Mathematics
1 answer:
creativ13 [48]3 years ago
4 0
Answer : 2ab^3+4a^2b-5ab+5
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What times what gives me -48 but adds to be -32?
oee [108]

Answer:

a couple of irrational numbers: -16±4√19, approximately {1.436, -33.436}

Step-by-step explanation:

Your question can be cast as the quadratic equation

  x² +32x -48 = 0

The solutions can be found using the quadratic formula:

  x = (-32 ±√(32² -4(1)(-48)))/(2(1)) = -16±√304 = -16±4√19

_____

<em>Comment on the equation we used</em>

We notice that when p and q are roots, the equation can be written ...

  (x -p)(x -q) = 0 = x² -(p+q)x +pq

You want p+q = -32, pq = -48, so the equation is ...

  x² -(-32)x +(-48) = 0

  x² +32x -48 = 0 . . . . . . with parentheses eliminated

5 0
3 years ago
The measure of angle θ is 7pi/4 . The measure of its reference angle is *Blank* °, and tan θ is *blank*
sukhopar [10]

Since the measure of angle \Theta is \frac{7\Pi }{4}

The measure of its reference angle = \frac{7\times 180^{\circ}}{4}

==315^{\circ}

Now we have to compute the value of \tan \Theta

\tan \Theta = \tan \frac{7\Pi }{4}

= \tan (2\Pi -\frac{\Pi }{4})

The value of ((2\Pi -\frac{\Pi }{4})) lies in the fourth quadrant. In fourth quadrant, the value of tan is always negative.

So, \tan (2\Pi -\frac{\Pi }{4})

= -\tan (\frac{\Pi }{4})

= -1.

5 0
3 years ago
The scale of a map says that 4 cm represents 5 km.
andriy [413]

Answer:

a. 3.2 cm

b. 6.25 km

Step-by-step explanation:

a.

(4 km)/(5 km) = 0.8

4 km is 0.8 of 5 km, so in the map it is 0.8 of 4 cm.

0.8 * 4 cm = 3.2 cm

Answer: 3.2 cm

b.

(5 cm)/(4 cm) = 1.25

5 cm is 1.25 times 4 cm, so it represents 1.25 * 5 km.

1.25 * 5 km = 6.25 km

Answer: 6.25 km

3 0
3 years ago
What's the solution for (9x + 5) - (4x + 3) ?
Vanyuwa [196]
(9x + 5) - (4x+3) = 0
9x - 4x + 5 - 3 = 0
5x + 2 = 0
5x = -2
5x/5 = -2/5
x= -2/5
5 0
3 years ago
Read 2 more answers
Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree
kompoz [17]

Answer:

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots x_{1}, x_{2}, x_{n} such that it can be written as: a(x - x_{1})*(x - x_{2})*...*(x-x_n), in which a is the leading coefficient.

Zero 1 with multiplicity 3.

So

p(x) = (x-1)^3

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

p(x) = (x-1)^3(x-4)^2

Zero -3 with multiplicity 1:

Considering the previous zeros:

p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is p(x) = (x-1)^3(x-4)^2(x+3)

8 0
3 years ago
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