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rosijanka [135]
2 years ago
7

Two forces produce equal torques on a door about the door hinge. The first force is at the midpoint of the door; the second forc

e is applied at the doorknob. Both fortes are applied perpendicular to the door. Which force has a greater magnitude?
the first force (at the midpoint).
the second force (at the doorknob).
the two forces are equal.
Physics
2 answers:
Andreas93 [3]2 years ago
6 0

Answer:

The doorknob

Explanation:

Hitting the door further out will cause greater magnitude than hitting it closer to where the door swings.

faltersainse [42]2 years ago
6 0

Answer:

The force at the midpoint of the door.

Explanation:

The torque produced in the door will be:

              T = rFsinθ

Here θ = 90 degrees so,

               T = rF  

At the midpoint of the door the moment arm is half than that of doorknob. So, to produce same torque we have to apply two times force at the midpoint of the door than the force at doorknob.

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How much Tim in minutes will it take a car driving at 90km/hr to travel 27 kilometers
astraxan [27]

Answer:

18min

Explanation:

v=d/t

t=d/v= 27/90 =0.3hrs =18min

6 0
3 years ago
Cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, ini
kakasveta [241]

The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

<h3>Conservation of Linear Momentum</h3>

Given Data

  • Mass of cart one M1  = 150kg
  • Initial Velocity U1 = 8m/s
  • Final VelocityV1 = 5 m/s

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

a. what is the speed of cart b after collision

substituting our given data we have

150*8+ 150*6 = 150*5+150*V2

1200 + 900 = 1200+ 150V2

2100 - 1200 = 150V2

900 = 150V2

Divide both sides by 150

V2 = 900/150

V2 = 6m/s

b. what is the total momentum of the system before and after collision

Total Momentum in the system is

Total momentum = Momentum before Impact+ Momentum after Impact

Total momentum = M1U1+M2U2 + M1V1+ M2V2

Total momentum = 1200 + 900 + 1200+ 900

Total momentum = 4200 kg m/s

Learn more about Conservation of Linear Momentum here:

brainly.com/question/7538238

6 0
2 years ago
If a person weighs 818 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that
alexandr402 [8]

Answer:

g'=63.74\ m/s^2

Explanation:

It is given that,

Weight of the person on Earth, W = 818 N

Weight of a person is given by the following formula as :

W=mg

g is the acceleration due to gravity on earth

m=\dfrac{W}{g}

m=\dfrac{818\ N}{9.8\ m/s^2}

m = 83.46 kg

The mass of an object is same everywhere. It does not depend on the location.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,

g'=\dfrac{W'}{m}

g'=\dfrac{5320\ N}{83.46\ kg}                

g'=63.74\ m/s^2

So, the acceleration due to gravity on that planet is 63.74\ m/s^2. Hence, this is the required solution.                                                                    

6 0
3 years ago
What are the factors of evaporation and give explanation​
Ira Lisetskai [31]
Temperature and rate of evaporation are proportional to each other. Surface area: As the surface area increases, the rate of evaporation increases. The surface area and rate of evaporation are proportional to each other. Humidity: The rate of evaporation decreases with an increase in humidity.
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2 years ago
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Is it possible for a population with a high birth rate to decrease in size.
matrenka [14]
Sure, if the mortality (death) rate is even higher than the birth rate.
7 0
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