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andriy [413]
3 years ago
9

What is the tension in the cord after the system is released from rest? Both masses (A and B) are 10-kg.

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

98 N.

Explanation:

Given data: mass= 10 kg,      gravity= 9.8 m/s2

required: tension in the cord=  ?

solution:

formula of tension= mass x gravity

by putting values of mass and gravity, we get

tension= 10 x 9.8

tension= 98 N.  <u>Ans</u>

If the mass of the object which is attached with both ends of cord is 10 kg, so the tension which is a opposite force of weight is 98 N.

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A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
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The acceleration of the sled will be 1.30 m/s². Force is defined as the product of mass and acceleration.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Given data;

m(mass of sled)=8 kg

Θ is the inclination of force= 50°

Force of friction,f=2.4 N.

The applied force at the given angle is resolved into the two-component as;

\rm F_h=F cos \theta \\\\ F_h= 20 cos 50 ^0 \\\\ F_h= 12.85 \ N

\rm F_v=F sin \theta \\\\  F_v=20 sin 50^0 \\\\   F_v=15.32 \ N

The net vertical force is zero;

\rm F_N=mg-Fsin50^0 \\\\ \rm F_N=8 \times 9.81 -15.32 \\\\ F_N=63.1 \ N \\\\

From Newton's second law the net force as;

\rm \sum F_{net}=ma \\\\ Fcos 60^0-f =ma \\\\ a=\frac{12.855-2.4}{8} \\\\a = 1.30 \ m/s^2

Hence, the acceleration of the sled will be 1.30 m/s².

To learn more about the force refer to the link;

brainly.com/question/26115859

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