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andriy [413]
3 years ago
9

What is the tension in the cord after the system is released from rest? Both masses (A and B) are 10-kg.

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

98 N.

Explanation:

Given data: mass= 10 kg,      gravity= 9.8 m/s2

required: tension in the cord=  ?

solution:

formula of tension= mass x gravity

by putting values of mass and gravity, we get

tension= 10 x 9.8

tension= 98 N.  <u>Ans</u>

If the mass of the object which is attached with both ends of cord is 10 kg, so the tension which is a opposite force of weight is 98 N.

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A student wished to add a new experiment to Chapter 2 by investigating whether the mass of water changes when it is heated. The
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Answer:

mass conservation is valid for all closed system where the mass will remain in the system always

Explanation:

Conservation of mass is applicable everywhere in classical physics

Here we can also apply mass conservation as we know that the initially the beaker and its water content is having total mass of 109.44 g

m_1 = 109.44 g

now when we heated it to higher temperature then its total mass will be lesser than the initial mass this is because some of the water may evaporate from the system.

Here if we repeat the same experiment with closed boundary then we can see that total mass will be conserved

So here mass conservation is valid for all closed system where the mass will remain in the system always

7 0
3 years ago
The Ptolemaic model of the universe:
harkovskaia [24]

Answer:

The Ptolemaic model of the universe <u><em>A) explained and predicted the motions of the planets with deferents and epicycles.</em></u>

Explanation:

Ptolemy of Alexandria built an explanation of the observed movements of the planets that remained in force for thirteen centuries. Ptolemy proposed a model of the Universe with the Earth in the center. In the model, the Earth remains stationary while the planets, the Moon and the Sun describe complicated orbits around it. In other words, Ptolemy devised a system in which he used epicycles, deferential and eccentric, and it was necessary to introduce an equating point to reproduce planetary movements. He proposed that:

a) Each planet revolves with constant velocity around a circle called an epicycle.

b) The center of the epicycle is located and moves with constant velocity around another circle called deferential.

c) The center of the deferent is located at a moving point, which travels with constant speed describing another circumference called eccentric.

d) The center of the eccentric coincides with the center of the Universe.

e) Since the Earth is not located in the center of the Universe, but very close to it, it was necessary to introduce an equating point, which is not on Earth, and from which you can see the planet move with constant speed.

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Finally, <u><em>The Ptolemaic model of the universe A) explained and predicted the motions of the planets with deferents and epicycles.</em></u>

8 0
3 years ago
Read 2 more answers
What two processes cycle water from the land to the atmosphere
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Chemical processes and physical processes are how water is cycled from land to the atmosphere.
6 0
3 years ago
How does the current model of the atom differ from<br> j j thomas model
bixtya [17]
Jj thomas' model contained electrons. 

The current model contains a nucleus with electrons orbiting around it. :)
4 0
3 years ago
A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per
FrozenT [24]

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

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Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

4 0
3 years ago
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