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andriy [413]
3 years ago
9

What is the tension in the cord after the system is released from rest? Both masses (A and B) are 10-kg.

Physics
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

98 N.

Explanation:

Given data: mass= 10 kg,      gravity= 9.8 m/s2

required: tension in the cord=  ?

solution:

formula of tension= mass x gravity

by putting values of mass and gravity, we get

tension= 10 x 9.8

tension= 98 N.  <u>Ans</u>

If the mass of the object which is attached with both ends of cord is 10 kg, so the tension which is a opposite force of weight is 98 N.

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Non-living factors in an ecosystem are<br><br> biotic<br><br> abiotic<br><br> antibiotic
zaharov [31]

Answer:

Abiotic

Explanation:

The non living factors of the ecosystem which is essential for the survival of living factors of the ecosystem are abiotic factors.

Examples for abiotic factors include temperature, sunlight, water, wind etc....

3 0
3 years ago
A 2.0 m length of wire is made by welding the end of a 120 cm long silver wire to the end of an 80 cm long copper wire. Each pie
Levart [38]

<u>Explanation</u>:

Resistivity of silver wire =1.47 e-8 ohm meter

Resistivity of copper wire = 1.72 \mathrm{e}-8 \text { ohm meter }

Resistance = Resistivity *length/cross sectional area

R=\rho_{L / A}

So,

\begin{aligned}&I=A\left(V / P_{A g} L_{A g}+P_{C u} L C_{U}\right)\\&1=8104 \mathrm{A}\end{aligned}

For E calculation

For copper

E = resistivity * current density

E = Resistivity * current/area

E=4.9298 \mathrm{V} / \mathrm{m}

For silver

E=4.213 \mathrm{V} / \mathrm{m}

Potential difference $=E^{*} L$

For silver

Potential difference = 4.213^{*} 1.2=5.055 \mathrm{V}

For copper

Potential difference =3.9438 \mathrm{V}

7 0
3 years ago
Coulomb's Law: Two identical small charged spheres are a certain distance apart, and each one initially experiences an electrost
Ahat [919]

Answer:

The magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force. ( ¹/₄ F)

Explanation:

The electrostatic force between two charges is given by Coulomb's law;

F = \frac{kQ_1Q_2}{r^2}

where;

Q₁ and Q₂ are the magnitude of the charges

r is the distance between the charges

k is Coulomb's constant

Since the charges are identical;

Q₁ = Q

Q₂ = Q

the electrostatic force experienced by each charge is given by;

F =  \frac{kQ^2}{r^2}

When each of the spheres has lost half of its initial charge;

Q₁ = Q/2

Q₂ = Q/2

F_2 = \frac{k(Q/2)(Q/2)}{r^2}\\\\ F_2 = \frac{k(Q)(Q)}{4r^2}\\\\F_2 = \frac{1}{4} (\frac{kQ^2}{r^2} )\\\\F_2 = \frac{1}{4} (F)

Therefore, the magnitude of electrostatic force on each charge is quarter of the magnitude of initial electrostatic force.

6 0
3 years ago
A machine: A- Makes work easier to do
Vlad1618 [11]

A: makes work easier to do.

5 0
3 years ago
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Pls helppppp my last question!
nexus9112 [7]

Answer:

load

a generator, a light bulb (load) and a closed switch

Explanation:

as explained in the other question, the fan is using generated electric energy to create mechanical movement. as such it is a load on the grid or circuit or net.

and electric power can only flow, if there is a closed (uninterupted) circuit from the power source to a load and back.

any open switch is an interruption of the circuit.

a buzzer is a kind of switch. it closes the circuit (and puts a load on) only when somebody presses it.

by the way, a closed circuit without a load will "destroy" (short circuit) the power source or at least the wires (burn through).

4 0
2 years ago
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