Hello there.
<span>In the context of depth perception, which of the following is a monocular cue?
</span><span>(C) Convergence
</span>
QUESTION: A pure jet engine propels and aircraft at 340 m/s through air at 45 kPa and -13C. The inlet diameter of this engine is 1.6 m, the compressor pressure ratio is 13, and the temperature at the turbine inlet is 557C. Determine the velocity at the exit of this engines nozzle and the thrust produced.
ANSWER: Due to the propulsion from the inlet diameter of this engine bring 1.6 m allows the compressor rations to radiate allowing thrust propultion above all velocitic rebisomes.
According to Newton's Second Law of Motion, the net force experienced by the system is equal to the mass of the system in question times the acceleration in motion. In this case, the net force is the difference of gravitational force and the force experience by the motion of the airplane. This difference is already given to be 210 N.
Net force = ma
210 N = (73 kg)(a)
a = +2.92 m/s²
Thus, the acceleration of the airplane's motion is 2.92 m/s² to the positive direction which is upwards.
Explanation:
The given data is as follows.
k = 130 N/m, 
= 17 cm = 0.17 m (as 1 m = 100 cm)
mass (m) = 2.8 kg
When the spring is compressed then energy stored in it is as follows.
Energy = 
Now, spring energy gets converted into kinetic energy when the box is launched.
So, = 
= 
= 1.34
v = 1.15 m/sec
Now,
Frictional force = 
= 
= 4.116 N
Also, Kinetic energy = work done by friction
1.8515 = 
d = 0.449 m
Thus, we can conclude that the box slides 0.449 m across the rough surface before stopping.
What is the weight of a 4.2 kg bowling ball on Mars?
Answer:
1.59 kg
Explanation:
The formula is:
<u>F = G((Mm)/r2)
</u>
F is the gravitational force between two objects,
G is the Gravitational Constant (6.674×10-11 Newtons x meters2 / kilograms2),
M is the planet's mass (kg),
m is your mass (kg), and
r is the distance (m) between the centers of the two masses (the planet's radius).
Hope this helps
--Jay
