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4 years ago

What is the formula for the nth term of a geometric sequence with a4 = 16 and r =1/2 ?

1 answer:

4 0

We have a4 = a1 * q^3;
Then, 16 = a1 * (1/8);
a1 = 128;
<span>The formula for the nth term of a geometric sequence is an = a1 * q^n;
an = 128 * (1/2)^n = (2^7)/(2^n) = 2^(7-n);</span>

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Which ratios are equal to each other? A. 1 : 16 and 2 : 8 B. 2 : 32 and 4 : 8 C. 1 : 64 and 4 : 16 D. 1 : 16 and 4 : 64

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The answer to the question is d

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3 years ago

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What is the difference of 54.59 and 26.61?

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3 years ago

Z^m-n (z^m+ z^m+n + z^n)

rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

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(−1)(−1)mn=(−1)n.

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3 years ago

F(x) = x + 2<br> g(x) = x-4<br> (f g)(x) =

Yanka [14]

Answer:

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4 years ago

The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me

Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

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3 years ago