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mash [69]
3 years ago
4

Finding an irrational number between which given pair of numbers supports the idea that irrational numbers are dense in real num

bers?

Mathematics
1 answer:
xeze [42]3 years ago
6 0

Answer:

The answer to this question is 3.33 and 1/3

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(9x−5/2) −(3−2x/3) −(8x−2/4 )=2
Ierofanga [76]
The answer for the equation is 21/5 or 4.2.

8 0
4 years ago
1. Find the domain and range of the function<br> f(x)=√1-4x².
slamgirl [31]

f(x) =  \sqrt{1 - 4{ x}^{2} }

1 - 4x {}^{2}  \geqslant 0

-  \infty  \:  \:  \:  \:  \:  \:  \:  \:  - 0.5 \:  \:  \:  \:  \:  \:  \:  \:  \: 0.5 \:  \:  \:  \:  \:  \:  \: \:   \infty  \\   -  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \: \:0  \:  \: \:  \:  \:   +  \:  \:  \:  \:0 \:  \:  \:  \:  \:   -

domain \\ [ \: -0.5 \: , \: 0.5 \: ]

g(x) = 1 - 4x {}^{2}  \\ g'(x) =  - 8x \\ g'(x) = 0 \\ x = 0 \\ g(0) = 1 - 4(0) = 1 \\ maximum \:  = 1

range  \\ [ \: 0 \:  ,  \: 1 \: ]

5 0
2 years ago
Read 2 more answers
Find the 50th term of 0,3,6,9
nalin [4]

\text{a}_1=0 \ \text{and} \ \text{a}_2=3\\\\\text{r}=\text{a}_2-\text{a}_1=3-0=3\\\\\text{a}_{50}=\text{a}_1+49\text{r}=0+49\cdot3=0+147=147\\\\\huge\boxed{\text{a}_{50}=147}

7 0
3 years ago
Ken receives $521 for maintenance on his grandmother's house and $347 for yard work. Which is the best estimate for how much mon
VikaD [51]

Answer:

521

+347

868

870

Step-by-step explanation:

8 0
3 years ago
A) Write the exponential equation to represent a house purchased for
dsp73

Answer:

= A(t) = 120000(1.06)^t   t = 1 year

We just add ^12 to equal 1/12 months.

Then use the notation below.

Step-by-step explanation:

We simply want to write an equivalent form of the same equation that will allow for the time period to be calculated in years.

For one year, t = 1, we want it to grow 6% = 1.06

Yearly Rate of Growth annual equation: = 7200

P(i) 7200/ 120000 x 100% = 6% per year growth rate

the yearly growth factor is 1 + appreciation rate = 1+i =1+0.06= 1.06

So time in years can be added to t

= A(t) = 120000(1.06)^t   t = 1 year

The yearly growth factor = 1.06

To equate monthly we add the exponent  t*12*1/12 before  120000(1.06)^t

then add 1/12 to replace ^t = monthly, or just keep the t= time

A(t) = 120000(1.06)^12t

4 0
3 years ago
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