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3 years ago

Pls help!!!! Match all of the angle and arc measures with the appropriate letter ? A through H

Mathematics

1 answer:

Charra [1.4K]3 years ago

8 0

Answer:

Step-by-step explanation:

a = 180 - 2(19) = 142°

b = 90° Triangle in a circle with one side as a diameter makes right triangle

c = 2(19) = 38°

d = 38°

e = 38°

f = 19° alternate angle

g = 19° equilateral triangle

h = 90 - 19 = 71°

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Help please help please help please

marissa [1.9K]

Answer:

x=5

Step-by-step explanation:

I'm pretty sure it's x=5 because if you multiply that and the quadratic function it is -12 1/2 not 12 1/2 (hope this helps :)

8 0

3 years ago

Read 2 more answers

The probability that an automobile being filled with gasoline also needs an

bogdanovich [222]

P(B | A) = probability of B given A

P(B | A) = P(B and A) / P(A)

thus

P(new oil filter | oil change) = P(both) / P(oil change)

= 0.14 / 0.25

(b) = 0.14 / 0.4

3 0

3 years ago

A computer is generating passwords. The computer generates six characters at random, and each is equally likely to be any of the

SVETLANKA909090 [29]

Answer:

0.1419 ( (if upper and lower cases are interchangeable)

0.348 ( if upper and lower cases are distinct letters)

Step-by-step explanation:

Each digit has 36 possible choices as 26+10

computer generates six characters

there are only 26 choices for letters only, (if we assume upper and lower cases are interchangeable)

For number of letters-only arrangements = $26^{6}$ = 308915776

For number of alphanumeric arrangements = $36^{6}$ = 2176782336

In order to find the probability of letters-only arrangements : $\frac{308915776}{2176782336}$

=><u>0.1419</u>

Now, in different scenario if upper and lower cases are not interchangeable.

We will have 26+26+10=62 alphanumeric choices, and 52 alphabetic choices

Therefore, probability of letters-only arrangements will be $\frac{52^{6} }{62^{6} }$

=<u>>0.348</u>

4 0

3 years ago

Read 2 more answers

Please answer this question based on the following data. SSTR = 6,750 H0: μ1= μ2=μ3=μ4 SSE = 8,000 Ha: at least one mean is diff

Nookie1986 [14]

Answer:

$P_v =P(F_{3,16}>4.5)=0.0180$

So on this case the best option for the answer would be:

between .01 and .025

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have $4$ groups and on each group from $j=1,\dots,5$ we have $5$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between=Treatment}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =6750$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8000$

And we have this property

$SST=SS_{between}+SS_{within}=6750+8000=14750$

The degrees of freedom for the numerator on this case is given by $df_{num}=k-1=4-1=3$ where k =4 represent the number of groups.

The degrees of freedom for the denominator on this case is given by $df_{den}=df_{between}=N-K=20-4=16$ .

And the total degrees of freedom would be $df=N-1=20 -1 =19$

We can find the $MSR=\frac{6750}{3}=2250$

And $MSE=\frac{8000}{16}=500$

And the we can find the F statistic $F=\frac{MSR}{MSE}=\frac{2250}{500}=4.5$

And with that we can find the p value. On this case the correct answer would be 3 for the numerator and 16 for the denominator.

$P_v =P(F_{3,16}>4.5)=0.0180$

So on this case the best option for the answer would be:

between .01 and .025

6 0

3 years ago

A random sample of 500 people is taken. 260 of them rent (as oppose to own) their residence. Compute a 95% confidence interval f

kirill [66]

Answer: A 95% confidence interval for the true proportion (p) will be (0.4762136, 0.5637864).

Step-by-step explanation:

Let p = True proportion of people rent their residence.

Given: n= 500

People rent their residence = 260

$p=\dfrac{260}{500}=0.52$

z-value for 95% confidence level = 1.96

A 95% confidence interval for the true proportion will be :

$p\pm z^*\sqrt{\dfrac{p(1-p)}{n}}$

$0.52\pm (1.96)\sqrt{\dfrac{0.52(1-0.52)}{500}}\\\\=0.52\pm(1.96\sqrt{\dfrac{0.2496}{500}})\\\\=0.52\pm 1.96\sqrt{0.0004992}\\\\=0.52\pm (1.96)(0.02234)\\\\=0.52\pm0.0437864\\\\=(0.52-0.0437864,\ 0.52+0.0437864)\\\\=(0.4762136,\ 0.5637864)$

A 95% confidence interval for the true proportion (p) will be (0.4762136, 0.5637864).

6 0

3 years ago