Answer:
(10, 1)
Step-by-step explanation:
It tells you that when you translate it you add 2 to the x-coordinate and subtract 7 from the y-coordinate. This means that the point E, (8, 8), would become (8 + 2, 8 - 7) or (10, 1).
A. The equation to find the distance of the flowerbed from the hive is: 
, where x is the distance.
B. The flowerbed is 2250 feet far from the hive.
<u><em>Explanation</em></u>
Suppose, the distance of the flowerbed from the hive is 
feet.
The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.
As, 
So, the time taken by the bee to reach the flowerbed 
seconds and the time taken to fly back to the hive 
seconds.
The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.
So, the equation will be.......
Thus, the distance of the flowerbed from the hive is 2250 feet.
we need to find the unit form in 2 tens and one multiplied with 10 .' we know that
21 is the 2 tens one
if we multiplied 21 with 10 we get 210 .
which means 21 tens are there in 210.which is the unit form of 210.
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
