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stiv31 [10]
3 years ago
13

Help with a few questions pleaseeeeee

Mathematics
1 answer:
mel-nik [20]3 years ago
3 0
29.99 * 3 =89.97 89.97 with 30% off = 62.98 and 5% of 62.98 =3.15 so 62.98 + 3.15 = 66.13$ 


180.00 + 14.95 + 8.95 = 203.09 - 15% = 173.44 + 4% = 180.38


5.65 + 5% of 5.65 = 5.93 

i think this is all right you might want to check my work!
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6,7,8 what are the inequality’s
yan [13]

Answer:

Its an equation, not an inequality

3 0
3 years ago
Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

8 0
3 years ago
Read 2 more answers
Skill in adding and subtracting decimals is useful for calculating ______ .
Sholpan [36]

Answer:

<u>the amount saved in buying a pair of $32.95 blue jeans on sale for $26.50</u>

Step-by-step explanation:

all are pretty good answers but that one is most reasonable

have a nice day :)

7 0
2 years ago
Read 2 more answers
Yvonne bought a car for $10,300. After 3 years, the value of the car was $6,250. The value of this car decreases exponentially o
Likurg_2 [28]

Answer:

A = $44,778.84

A = P + I where

P (principal) = $10,300.00

I (interest) = $34,478.84 or 12 months

Step-by-step explanation:

Given: Yvonne bought a car for $10,300. After 3 years, the value of the car was $6,250. 50%

To find: In approximately what number of additional months will the value of Yvonne’s car be 50% of the price she originally paid?

Formula: (\frac{interest rate}{number of payments}) × loan principal = interest

Solution:  Divide your interest rate by the number of payments you’ll make in the year (interest rates are expressed annually). So, for example, if you’re making monthly payments, divide by 12. Multiply it by the balance of your loan, which for the first payment, will be your whole principal amount.

(This gives you the amount of interest you pay the first month.)

First, convert R as a percent to r as a decimal

r = R/100

r = 50/100

r = 0.5 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 10,300.00(1 + 0.5/12)(12)(3)

A = 10,300.00(1 + 0.041666667)(36)

A = $44,778.84

Henceforth:

The total amount accrued, principal plus interest, with compound interest on a principal of $10,300.00 at a rate of 50% per year compounded 12 times per year over 3 years is $44,778.84.

6 0
2 years ago
PLEASE HELP!!!! THANKS!!!! (WILL MARK BRAINLIEST)
Lelechka [254]

Answer:11/26=0.423076923077 so it could be .0423

Step-by-step explanation:

7 0
2 years ago
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