Answer:
neither
geometric progression
arithmetic progression
Step-by-step explanation:
Given:
sequences: 


To find: which of the given sequence forms arithmetic progression, geometric progression or neither of them
Solution:
A sequence forms an arithmetic progression if difference between terms remain same.
A sequence forms a geometric progression if ratio of the consecutive terms is same.
For
:

Hence,the given sequence does not form an arithmetic progression.

Hence,the given sequence does not form a geometric progression.
So,
is neither an arithmetic progression nor a geometric progression.
For
:

As ratio of the consecutive terms is same, the sequence forms a geometric progression.
For
:

As the difference between the consecutive terms is the same, the sequence forms an arithmetic progression.
Answer:
34+4a
Step-by-step explanation:
-2a+7-3(-9-4a)
➡ -2a+7+27+12a
➡34+10a
Answer:

Step-by-step explanation:
<u><em>The correct question is</em></u>
What value of b will cause the system to have an infinite number of solutions?
y = 6x – b
–3x + 1/2y = –3
we have
----->equation A
-----> equation B
we know that
If the system has infinite number of solutions then, the equation A must be equal to the equation B
so
isolate variable y in the equation B

Multiply by
both sides

-------> new equation B
To find out the value of b, equate equation A and equation B


Vertical angles are equal to each other:
∠2 = ∠3
5 + 4y = 6y - 25
→ 30 = 2y
→ 15 = y
∠2 = 5 + 4y = 5 + 4(15) = 5 + 60 = 65
linear pairs equal 180:
∠1 + ∠2 = 180
→ ∠1 + 65 = 180
→ ∠1 = 115
2x = 15 - 3x -- add 3x to both sides
5x = 15 -- divide both sides by 5
x = 3 -- simplest form