Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
<em>f</em>
<em> t</em>
<em> t</em>
<em> t</em>
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f <em>f</em> f
f <em>t</em> t
t <em>t</em> f
t <em>t</em> t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
<em>f f </em>
<em> t t</em>
<em> t t</em>
<em> t t</em>
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
no you cannot conclude that state c costs more than a and b because you do not know the value of state a and b
Yess, such fun so
q=number of quarter
n=number of nickles
q+n=63
9.15=915 cents
25 cents=1 q
5 cents=1 n so
915=25q+5n
915=5(5q+n)
divide by 5
183=5q+n
we also have q+n=63
subtract q from both sides
n=63-q
subsitute 63-q for n in second equation
183=5q+63-q
add like terms
183=4q+63
subtract 63 from both sides
120=4q
divdie by 4
30=q
there were 30 quarters
subsitute
63=30+n
subtract 30
33=n
30 quarters
33 nicles
