Mole fraction of ethylene is = 0.144
How to find mole fraction ?
As, Given that vapor pressure = 7.88 torr
pure water vapor pressure = 9.21 torr
∆P solvent = (X Solute)(Pº solvent)
∆Psolvent = change in vapor pressure = 9.21 torr - 7.88 torr = 1.33 torr
Xsolute = mole fraction of the solute = ?
Pºsolvent = vapor pressure of the pure solvent = 9.21 torr
1.33 torr = (Xsolute)(9.21)
Xsolute = 1.33 torr/9.21 torr)
Xsolute = 0.144
Hence the mole fraction of ethylene is = 0.144
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