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o-na [289]
2 years ago
14

The process of generating electricity from dams and nuclear power plants is very different, but some of the energy transformatio

ns are the same. Which energy transformations occur in both dams and nuclear power plants? Check all that apply.
Chemistry
2 answers:
Snezhnost [94]2 years ago
7 0

Answer:

Explanation:

Kinetic energy to mechanical and mechanical to electrical

Alexxx [7]2 years ago
3 0

Answer:

Kinetic energy to mechanical energy, and mechanical energy to electrical energy.

Explanation:

From the Law of conservation of Energy, which state that energy can neither be created nor destroyed but can be transformed from one form to another. Energy transformation is essential in science and technology, in the process of generating electricity from dams and nuclear power plants

some of the energy transformations are the same, the energy transformations occur in both dams and nuclear power plants is Kinetic energy to mechanical energy, and mechanical energy to electrical energy. Kinectic energy is the energy in motion which means the dams is a running water and posses a Kinectic energy then it's is been convert to mechanical energy (which is the macroscopic energy) then to electrical energy by producing light.

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Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an
garri49 [273]

Explanation:

The given data is as follows.

      T = 120^{o}C = (120 + 273.15)K = 393.15 K,  

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So,            x_{1} = 0.5   and   x_{2} = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

               p^{sat}_{1} (393.15 K) = 9.2 bar

               p^{sat}_{1} (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

                 p_{1} = x_{1} \times p^{sat}_{1}

                            = 0.5 \times 9.2 bar

                             = 4.6 bar

and,           p_{2} = x_{2} \times p^{sat}_{2}

                         = 0.5 \times 10.5 bar

                         = 5.25 bar

Therefore, the bubble pressure will be as follows.

                           P = p_{1} + p_{2}            

                              = 4.6 bar + 5.25 bar

                              = 9.85 bar

Now, we will calculate the vapor composition as follows.

                      y_{1} = \frac{p_{1}}{p}

                                = \frac{4.6}{9.85}

                                = 0.467

and,                y_{2} = \frac{p_{2}}{p}

                                = \frac{5.25}{9.85}

                                = 0.527  

Calculate the dew point as follows.

                     y_{1} = 0.5,      y_{2} = 0.5  

          \frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}

           \frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}

             \frac{1}{P} = 0.101966 bar^{-1}              

                             P = 9.807

Composition of the liquid phase is x_{i} and its formula is as follows.

                   x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{9.2}

                               = 0.5329

                    x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}

                               = \frac{0.5 \times 9.807}{10.5}

                               = 0.467

4 0
3 years ago
Pls help and show work!!!
kumpel [21]

Answer:

44.9g

Explanation:

You have to convert grams of CH4 to moles, use the mole-to-mole ratio of CH4 to water, and convert back to grams.

(20.0g CH4)(1 mol CH4/16.04g)(2 mol H2O/1 mol CH4)(18.01 g H2O/ 1 mol) = 44.9127 g

Hope this helps!

5 0
2 years ago
Read 2 more answers
1 km is equal to<br><br> 100 m<br> 10,000 dm<br> 1,000 mm<br> 1,000 cm
vovikov84 [41]
The answer would be B) 10,000 DM is equal to 1 kilometer.
3 0
3 years ago
You are confronted by a phosphorus atom. this atom has 15 protons and 17 neutrons. how many electrons does it have
bogdanovich [222]
15 electrons if it is not an ion

8 0
2 years ago
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Suppose Highlinium-308 can also undergo positron emission
____ [38]

Answer:

The atomic number of burienium will be 307.

Explanation:

During positron emission proton is converted into the neutron and one electron neutrino with positron is released. It means the atomic number will be reduce by one and atomic mass remain same.

For example:

²³Mg₁₂    →     ₁₁Na²³+ e⁺+ Ve

Similarly, when highlinium-308 undergoes positron emission the new element burienium is produced and the atomic number will be 307 while atomic mass remain same.

Properties of beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

4 0
3 years ago
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