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Alborosie
2 years ago
11

a solution containing ethylene glycol and water has a vapor pressure of 7.88 torrtorr at 10 ∘c∘c . pure water has a vapor pressu

re of 9.21 torrtorr at 10 ∘c∘c . what is the mole fraction of ethylene glycol in the solution?
Chemistry
1 answer:
Nuetrik [128]2 years ago
3 0

Mole fraction of ethylene is = 0.144  

How to find mole fraction ?

As, Given that vapor pressure = 7.88 torr

pure water vapor pressure = 9.21 torr

∆P solvent = (X Solute)(Pº solvent)

∆Psolvent = change in vapor pressure = 9.21 torr - 7.88 torr = 1.33 torr

Xsolute = mole fraction of the solute = ?

Pºsolvent = vapor pressure of the pure solvent = 9.21 torr

1.33 torr = (Xsolute)(9.21)

Xsolute = 1.33 torr/9.21 torr)

Xsolute = 0.144

Hence the mole fraction of ethylene is = 0.144  

learn more about mole fraction is here :

brainly.com/question/14783710

#SPJ4

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