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Alborosie
1 year ago
11

a solution containing ethylene glycol and water has a vapor pressure of 7.88 torrtorr at 10 ∘c∘c . pure water has a vapor pressu

re of 9.21 torrtorr at 10 ∘c∘c . what is the mole fraction of ethylene glycol in the solution?
Chemistry
1 answer:
Nuetrik [128]1 year ago
3 0

Mole fraction of ethylene is = 0.144  

How to find mole fraction ?

As, Given that vapor pressure = 7.88 torr

pure water vapor pressure = 9.21 torr

∆P solvent = (X Solute)(Pº solvent)

∆Psolvent = change in vapor pressure = 9.21 torr - 7.88 torr = 1.33 torr

Xsolute = mole fraction of the solute = ?

Pºsolvent = vapor pressure of the pure solvent = 9.21 torr

1.33 torr = (Xsolute)(9.21)

Xsolute = 1.33 torr/9.21 torr)

Xsolute = 0.144

Hence the mole fraction of ethylene is = 0.144  

learn more about mole fraction is here :

brainly.com/question/14783710

#SPJ4

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When heat energy is removed, two changes are observed:
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4 0
2 years ago
2
Gemiola [76]

Answer:

the physical and chemical properties of the products are different from the reactants

Explanation:

A chemical reaction involves the chemical combination of two or more elements/compounds called Reactants to give one or more different elements/compounds called Products. A chemical reaction occurs in such a way that the atoms of the reactants are restructured to form product(s) that is/are entirely different from the reactants.

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7 0
3 years ago
15.3 g of nano3 were dissolved in 100g of water in a calorimeter. The temperature of the water drops from 25.00°c to 21.56°c. Ca
Arturiano [62]

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0.259 kJ/mol ≅ 0.26 kJ/mol.

Explanation:

  • To solve this problem, we can use the relation:

<em>Q = m.c.ΔT,</em>

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c is the specific heat of water (c of ice = 4.186 J/g.°C).

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<em>∵ Q = m.c.ΔT</em>

∴ Q = (100.0 g)(4.186 J/g.°C)(-3.44°C) = -1440 J = -1.44 kJ.

<em>∵ ΔH = Q/n</em>

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3 years ago
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