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laiz [17]
3 years ago
6

Subtraia do quadrado de 3/4,o cubo de 1/2.que resultado encontrara

Mathematics
2 answers:
vova2212 [387]3 years ago
5 0

A resposta para esta equação é 7/16.

NNADVOKAT [17]3 years ago
4 0

Is your question in spanish?

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A 15 oz box of cereal cots 3.75 how much does a 21 oz box cost
MariettaO [177]

Answer:

$5.25

Step-by-step explanation:

3.75/15= 0.25 per oz

0.25* 21= 5.25

4 0
3 years ago
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Two and three fourths plu one and three eight
crimeas [40]
2 3/4 + 1 3/8 = 4.125 and there is your answer
6 0
3 years ago
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What is 1,334 divided by 23? A) 53 B) 56 C) 57 D) 58<br><br><br> The answer is D 58
Sindrei [870]
D is the answer?
Hope it helped!
5 0
3 years ago
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You are tasked with constructing a rectangular box with a square base, an open top, and a volume of 184 in3. Determine what the
Rudik [331]

The dimension of the box should be 1.7×1.7×3.58 in inches, applying minimization of surface area.

Dimensions to Minimize the Surface Area of the Box

It is given that the box is square based with an open top.

⇒ The box has one square and 4 rectangles

Thus, the total surface area of the box is given as,

S= a²+ab+ab+ab+ab  

S= a²+4ab ______________ (1)

Here, a is the side of the squared base and length of the rectangular sides of the box, b is the breath of the rectangular sides of the box.

This equation is later used for minimization of the surface area.

Also, the volume, V = a²b

It is also given that volume of the box is 184 in³.

⇒ 184 = a²b _____________ (2)

Forming a One-Variable Equation

From equation (2), b=184/a²

Now, substitute this value of b in equation (1) to get,

S = a² + 4a(184/a²)

S = a² + 4(184/a)

S = a² + 736/a

Minimization of Surface Area to find the Dimension

We require a dimension that will minimize the surface area of the box. Hence, applying minimization surface area, dS/da = 0

dS/da = 2a -736/a²

0 = 2a -736/a²

⇒ 0 = 2a³- 736

2a³ = 736

a³ = 736/2

a³ = 368

a = ∛368

a= 7.17 in

∵V = a²b

184 = (7.17)²b

b = 184/7.17²

b = 184/51.4089

b = 3.58 in

Therefore, 1.7×1.7×3.58 in inches is the required dimension for the box, using minimization of surface area..

Learn more about minimization here:

brainly.com/question/17135620

#SPJ4

5 0
2 years ago
I do roadwork site 20 cones are placed on 50 feet of road. at this rate, how many cones are placed along 35 feet of road?
satela [25.4K]
You would cross multiply for this.
\frac{20}{50}  =  \frac{x}{35}

20 · 35 = 700
Then you would divide.
700 ÷ 50 = 14

There would be 14 cones placed along 35 feet of road.
5 0
3 years ago
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