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ArbitrLikvidat [17]
4 years ago
6

2(y - 6) = 3(y - 4) - y Simplify.

Mathematics
1 answer:
eimsori [14]4 years ago
7 0

First Distribute:

2y-12=3y-12-y

Then combine like terms:

2y-12=2y-12

Then isolate y by adding 12 to each side, then subtracting 2y to each side.

Answer: undefined 0=0


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Can someone help me please
lukranit [14]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
2/3+q=1/2 what is Q
JulsSmile [24]

Q=rational number=1/6

2/3+q=1/2=1/6

4 0
3 years ago
(2a+b)^2 how do you do this
gulaghasi [49]

•  Expand (2a + b)²:

(2a + b)²

= (2a + b) · (2a + b)


Multiply out the brackets by applying the distributive property of multiplication:

= (2a + b) · 2a + (2a + b) · b

= 2a · 2a + b · 2a + 2a · b + b · b

= 2²a² + 2ab + 2ab + b²


Now, group like terms together, and you get

= 2²a² + 4ab + b²

= 4a² + 4ab + b²    <———    expanded form  (this is the answer).


I hope this helps. =)


Tags:  <em>special product square of a sum algebra</em>

3 0
3 years ago
Troy is going to Spain and needs to convert his dollars to euros. He knows that when he goes, $5.00 is equivalent to about 3.45
Annette [7]
125/5=25
25*3.45=86.25

86.25 euros

4 0
3 years ago
Read 2 more answers
PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)
trapecia [35]

\huge \bf༆ Answer ༄

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \:   \:  \:  \: \:  (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:13x + 5y = 670 \:  \:  \:  \:  \: (2)

multiply the equation (2) with 2 [ it won't change the values ]

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260 \: \:  \:  \:   \:  \:  \:  \:  \: (1)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y = 1340 \:  \:  \:  \:  \: (3)

Now, deduct equation (1) from equation (3)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:26x + 10y - 2x - 10y = 1340 - 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:24x = 1080

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 1080 \div 24

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x = 45

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2x + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(2 \times 45) + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:90 + 10y = 260

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 260 - 90

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:10y = 170

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 170 \div 10

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = 17

Hence, each van can carry (y) = 17 students in total.

5 0
3 years ago
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