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anygoal [31]
3 years ago
11

If the temperature outside was 63°F at 5:00 p.m., but it fell 21 degrees by 10:00 p.m., what is the temperature at 10:00 p.m.?

Mathematics
2 answers:
marissa [1.9K]3 years ago
4 0

Answer:

42°

Step-by-step explanation:

Subtract: 63 - 21 = 42°

Troyanec [42]3 years ago
3 0

Answer:

42°F

Step-by-step explanation:

63-21=42°F

if it fell, it means it went down, so it got colder

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HELP ASAP
lora16 [44]
I solved it on a piece of paper. I can not answer why I got the same answer, but I hope my method helped

3 0
2 years ago
Assuming that π = 3.14, how much air will it take to fill a sports ball with a radius of 6 cm?
madam [21]

Answer:

I would need more information but I believe its A

Step-by-step explanation:

4 0
3 years ago
Victor Malala has a net income of $1240.00 per month. If he spends $150.00 on food, $244.00 on a car payment, $300.00 on rent, a
Nady [450]
Net Income: I=$1,240.00
Food: F=$150.00
Car payment: C=$244.00
Rent: R=$300.00
Saving: S=$50.00
Other things: O=?

F+C+R+S+O=I
$150.00+$244.00+$300.00+$50.00+O=$1240.00
Solving for O:
$744.00+O=$1240.00
$744.00+O-$744.00=$1240.00-$744.00
O=$496.00

Percent of his net income Victor can spend on other things: P=?
P=(O/I)*100%
P=($496.00/$1240.00)*100%
P=(0.40)*100%
P=40%

Answer: 40% of his net income Victor can spend on other things.


3 0
3 years ago
Whats the roots of the following three problems:
klemol [59]

QUESTION 1

The given function is

f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}

We simplify to get;

f(x)=\frac{x-3}{x+2}

This function is equal to zero when x-3=0

\Rightarrow x=3

QUESTION 2

The given function is

f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}

f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}

We factor to get;

f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}

f(x)=\frac{5(x-1)}{(2x-3)}

This function equals zero when

5(x-1)=0

x=1

QUESTION 3

The given function is

f(x)=\frac{x^3-8}{x^2-6x+8}

We factor to get,

f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}

f(x)=\frac{x^2+2x+4}{x+4}

The function equals zero when x^2+2x+4=0

D=b^2-4ac

D=2^2-4(1)(4)

D=-12

Hence the equation has no real roots.

The complex roots are

x=-\sqrt{3}i-1 or x=-1+\sqrt{3}i

4 0
3 years ago
write the equation for the transformation of the graph of y=f(x). use the form f(x)=a(x-h)+k. 13. translated 2 units left and 7
sergey [27]
13)  f(x)  =  a ( x + 2 ) - 7 

14) f(x) = 3 ( x - 5 ) + 2 
3 0
3 years ago
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