(2a+b)^2 how do you do this
1 answer:
• Expand (2a + b)²: (2a + b)² = (2a + b) · (2a + b) Multiply out the brackets by applying the distributive property of multiplication: = (2a + b) · 2a + (2a + b) · b = 2a · 2a + b · 2a + 2a · b + b · b = 2²a² + 2ab + 2ab + b² Now, group like terms together, and you get = 2²a² + 4ab + b² = 4a² + 4ab + b² <——— expanded form (this is the answer). I hope this helps. =) Tags: <em>special product square of a sum algebra</em>
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