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3 years ago

(2a+b)^2 how do you do this

1 answer:

3 0

• Expand (2a + b)²:

(2a + b)²

= (2a + b) · (2a + b)

Multiply out the brackets by applying the distributive property of multiplication:

= (2a + b) · 2a + (2a + b) · b

= 2a · 2a + b · 2a + 2a · b + b · b

= 2²a² + 2ab + 2ab + b²

Now, group like terms together, and you get

= 2²a² + 4ab + b²

= 4a² + 4ab + b² <——— expanded form (this is the answer).

I hope this helps. =)

Tags: <em>special product square of a sum algebra</em>

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The old time train museum is raising the price of tickets for train rides.Tickets used to cost $4.80 each. The new ticket price

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Only add $4.80 + $1.25

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3 years ago

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21. In 4 + In(4x - 15) = In(5x + 19)

Alexxx [7]

Answer:

$x=-30;\quad \:I\ne \:0$

Step-by-step explanation:

$In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)$

$\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\$

$\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\$

$\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:$

$\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0$

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3 years ago

Please Help Fast!!!!!!!!

statuscvo [17]

5/3

= 1 2/3 or 1.667

Hope this helps!

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3 years ago

I need help..What’s the answer

RSB [31]

Answer:

D. 3,750

Step-by-step explanation:

Use proportions to solve:

125/500 = x/15000

Cross multiply:

125*15000 = 1,875,000

1,875,000/500 = 3,750

x = 3,750

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3 years ago

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Mars2501 [29]

Hello!

Answer:

4- 8, 12, 16, 20, 24 ect keep adding 4

8- 16, 24, 32, 40, 48 ect keep adding 8

Step-by-step explanation:

both- 16, 24, 40, 48

Hope this helps have a good day! <3

Plz mark brainliest when u get the chance!

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