I’m like 99 Percent sure this is right.
Experimental Variable: Orange Trees
IND. Variable: The Fungi
DEP. Variable: Fruit Weight
Control Group: Group A
Experimental Group: Group B
Hope this helps!
Answer:
Water is least dense at 0°C (freezing point)
One risk for accessing carbon from the ground is that it may cause soil contamination. Soil when exposed to large amount of gases and other organically decaying materials can absorb these into their make-up. Fossil fuels are extracted from the ground through drilling processes. When the drilling is unsuccessful, pockets created within the soil can create areas for contamination. When soil is contaminated by fossil fuels, it can no longer be use for agricultural purposes.
The answer is A. anther and ovary.
The female part of an angiosperm flower is called a pistil and it consists of a style, stigma and ovary. The male part of an angiosperm flower is called a stamen and it consists of an anther and corolla. Thus, among all choices, choice A is the answer.
Choice B - anther is the male part of the flower, but sepal is a protective part of the flower and not reproductive.
Choice D - stigma is the female part of the flower, but sepal is a protective part of the flower and not reproductive.
Choice C - "vary" is not a word, but it is a mistake and it should be "ovary," the answers could be both choice A and C.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%