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3 years ago

14

Matt's family rented a car to go on vacation the cost of the rental was $50 plus an additional $0.20 per mile driven his family

drives drove 300 miles how much did they spend for the car

1 answer:

bagirrra123 [75]3 years ago

6 0

1) 300miles X $0.20 = $60

2) $50 + $60 = $110

They spent $110 for the car.

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In which set are all of the numbers solutions to this inequality?

Nastasia [14]

The answer is answer choice B,

B) {-2, -1, 0, 1}

~~

I hope that helps you out!!

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3 years ago

Which property is used 2(x+4)=2x+8

Elenna [48]

Answer:

Apply the distributive property

2x+2(4)=2x+8

Multiply 2 by 4

2x+8=2x+8

Move all terms containing x to the left and subtract 2x

2x+8-2x=8

Combine the opposite terms

2x+8-2x

Subtract 2x from 2x

0+8=8

8=8

All real number

Step-by-step explanation:

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3 years ago

The picture shows a feeding trough that is shaped like a right prism. (Picture is shown at the bottom!!)

AlexFokin [52]

Height of the trapezoids = sqrt (17^2 - 8^2) = 15cms
base = 19 cms

(b) area of each trapezoid = 15/2 (35 + 19) = 405 cm^2

Total area painted blue = 2*405 = 810 cm^2

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So one piece of sandpaper ( can sand up to 80 cm) will not be enough to sand all of the edges.

4 0

3 years ago

3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo

salantis [7]

Answer:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the mean is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And if we replace the values obtained we got this:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

6 0

3 years ago

Can anyone help me find the value pls?

Flauer [41]

The inside angle for B, which is labeled x is the same as the outside angle of D which is labeled as 72, so we know x = 72.

In a parallelogram two angles next to each other equal 180, so angle A and angle B equal 180.

We know B = 72, so A = 180-72 = 108

Angle A is divided in 2 by angle y, so y = 108/2 = 54

Answers: x = 72

Y = 54

4 0

3 years ago