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3 years ago

14

Matt's family rented a car to go on vacation the cost of the rental was $50 plus an additional $0.20 per mile driven his family

drives drove 300 miles how much did they spend for the car

1 answer:

bagirrra123 [75]3 years ago

6 0

1) 300miles X $0.20 = $60

2) $50 + $60 = $110

They spent $110 for the car.

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Find the mean, median, mode, and range of the data set,

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Quadrilateral CARD is similar to quadrilateral SNOW.

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3 years ago

Both the La Plata river dolphin (Pontoporia blainvillei) and

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Answer:

<em>1. A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin; 2. The radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball; 3. The volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

Step-by-step explanation:

If we expressed a number as:

$\\ N = a * 10^{b}$ (1)

Where

$\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10}$ (2)

or

$\\ 1 \leq a < 10$ (3)

Then, <em>b</em> represents the <em>order of magnitude </em>of such a number (<em>Order of magnitude (2020), </em>in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The<em> La Plata river dolphin</em> weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the <em>scientific notation</em>):

$\\ 30kg \leq Dolphin_{weight} \leq 50kg$

$\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg$

$\\ 35000kg \leq Whale_{weight} \leq 40000kg$

$\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg$

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

$\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)$

$\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)$

Then

$\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}$

$\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}$

Thus

<em>A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin.</em>

<h3>Second case</h3>

Following the same reasoning, we can conclude that <em>the radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball:</em>

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}$

$\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = 10^{1-0} = 10^{1}$

<h3>Third case</h3>

For this case, we need to calculate <em>the volume of a sphere</em> for both radii (1cm and 10cm).

The volume of a sphere is

$\\ V_{sphere} = \frac{4}{3}*\pi*R^{3}$

Then, the volume of the <em>ball of radius 1cm</em> is:

$\\ V_{radius=1} = \frac{4}{3}*\pi*(1cm)^{3}$

$\\ V_{radius=1} \approx 4.19*10^{0}cm^{3}$

And, the volume of the <em>ball of radius 10cm</em> is:

$\\ V_{radius=10} = \frac{4}{3}*\pi*(10cm)^{3}$

$\\ V_{radius=10} \approx 4.19*10^{3}cm^{3}$

Thus

$\\ \frac{10^{3}}{10^{0}} = 10^{3}$

As a result, <em>the volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

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3 years ago

Marcos make his famous salad Jackson by mixing 5 1/4 ounces of olive oil with one and a half ounces of vinegar. How much vinegar

Anika [276]

Answer:

8 ounces of vinegar

36 ounces of dressing

Step-by-step explanation:

Marco makes his famous salad Jackson by mixing 5 1/4 ounces of olive oil with 1 1/2 ounces of vinegar.

Olive oil Vinegar

5 1/4 1 1/2

28 x

Write a proportion:

$\dfrac{5\frac{1}{4}}{28}=\dfrac{1\frac{1}{2}}{x}\\ \\5\dfrac{1}{4}\cdot x=28\cdot 1\dfrac{1}{2}\ [\text{Cross multiply}]\\ \\\dfrac{21}{4}x=28\cdot \dfrac{3}{2}\\ \\\dfrac{21 x}{4}=42\\ \\x=42\div \dfrac{21}{4}\\ \\x=42\cdot \dfrac{4}{21}\\ \\x=2\cdot 4\\ \\x=8\ ounces$

Marco will make

$28+8=36$ ounces of dressing

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3 years ago

Based on the Empirical Rule, what percent of the data would fall AFTER the first standard deviation GREATER than the mean?

Tcecarenko [31]

13.5% i thinkkkkkkkkkk

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3 years ago