Answer:16/1
Step-by-step explanation:
Answer:
Number 1: x≈4.9412824
Number 2: x=3√10,−3√10x=310,-310
Decimal Form:
x=9.48683298...−9.48683298...
Number 3: x≈−5.04938819
Number 4: x=−1+2√6,−1−2√6x=-1+26,-1-26
Decimal Form:
x=3.89897948…,−5.89897948…
Number 5: x=−7+√93,−7−√93x=-7+93,-7-93
Decimal Form:
x=2.64365076…,−16.64365076…
Number 6: x=1+i√3910,1−i√3910
Answer:
95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].
Step-by-step explanation:
We are given that 15% of a random sample of 300 U.S. public high school students were obese.
Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;
P.Q. =
~ N(0,1)
where,
= sample % of U.S. public high school students who were obese = 15%
n = sample of U.S. public high school students = 300
p = population percentage of all U.S. public high school students
<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>
<u></u>
<u>So, 95% confidence interval for the population proportion, p is ;</u>
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 <
< 1.96) = 0.95
P(
<
<
) = 0.95
P(
< p <
) = 0.95
<u>95% confidence interval for p</u> = [
,
]
= [
,
]
= [0.110 , 0.190]
Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].
B, since 13 ppl have 2 or less TVs while 12 have 3 or more