x = 2
<em>right</em><em> </em><em>option</em><em> </em><em>is</em><em> </em>(E).
Step-by-step explanation:
f(x) = x³ - 3x² + 12 in interval [-2, 4]
{taking f'(x) by doing derivative of f(x)}
f'(x) = 3x² - 6x
.•. f'(x) = 0
0 = 3x² - 6x
0 = 3x(x - 2)
0 = x - 2
x = 2
Answer:
x = 12
Step-by-step explanation:
Solve for x:
360 - 30 x = 0
Subtract 360 from both sides:
(360 - 360) - 30 x = -360
360 - 360 = 0:
-30 x = -360
Divide both sides of -30 x = -360 by -30:
(-30 x)/(-30) = (-360)/(-30)
(-30)/(-30) = 1:
x = (-360)/(-30)
The gcd of 360 and -30 is 30, so (-360)/(-30) = (-(30×12))/(30 (-1)) = 30/30×(-12)/(-1) = (-12)/(-1):
x = (-12)/(-1)
(-12)/(-1) = (-1)/(-1)×12 = 12:
Answer: x = 12
Answer:
you have to divide by 4 not subtracted.
Step-by-step explanation:
Answer:
(0, -6/5)
(-3, 0)
Step-by-step explanation:
y-intercept is when x is 0.
x-intercept is when y is 0.
First, I would solve the second parenthesis.
(4xy^3)^2
Distribute
(4^2 x^2 y^6)
4 x 4 = 16
Now, combine like terms
3x^2 x 4x^2 = 12x^4
y^2 x y^6 = y^12
So, the answer would be 12x^4 y^12
Hmm actually I'm not sure. I did this about two years ago so I don't really remember sorry if this is really wrong
