Answer:
Corresponding Binary numbers are as following:
A4693FBC=10100100011010010011111110111100.
B697C7A1
= 10110110100101111100011110100001.
Explanation:
A single digit hexadecimal number is a 4 bit binary number.So for each hexadecimal bit we have to find the corresponding 4 bit binary number.
A=1010
4=0100
6=0110
9=1001
3=0011
F=1111
B=1011
C=1100
and write them in the same sequence of their hexadecimal number.
A4693FBC=10100100011010010011111110111100.
B=1011
6=0110
9=1001
7=0111
C=1100
7=0111
A=1010
1=0001
B697C7A1
= 10110110100101111100011110100001.
Answer:
The program written in C++ is as follows'
#include<iostream>
using namespace std;
int main()
{
string names[3];
cout<<"Please enter three names: "<<endl;
for (int i = 0; i< 3;i++)
{
cin>>names[i];
}
for (int i = 2; i>= 0;i--)
{
cout<<names[i]<<endl;
}
return 0;
}
Explanation:
This line declares an array for 3 elements
string names[3];
This line prompts user for three names
cout<<"Please enter three names: "<<endl;
This following iteration lets user input the three names
for (int i = 0; i< 3;i++) { cin>>names[i]; }
The following iteration prints the three names in reverse order
for (int i = 2; i>= 0;i--) { cout<<names[i]<<endl; }
Answer:
false
Explanation:
Ms word is only an application software
Answer:
Explanation:
#include<iostream>
#include<ctime>
#include<bits/stdc++.h>
using namespace std;
double calculate(double arr[], int l)
{
double avg=0.0;
int x;
for(x=0;x<l;x++)
{
avg+=arr[x];
}
avg/=l;
return avg;
}
int biggest(int arr[], int n)
{
int x,idx,big=-1;
for(x=0;x<n;x++)
{
if(arr[x]>big)
{
big=arr[x];
idx=x;
}
}
return idx;
}
int main()
{
vector<pair<int,double> >result;
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
int choice;
cin>>choice;
while(choice!=2)
{
int n,m;
cout<<"Enter N"<<endl;
cin>>n;
cout<<"Enter M"<<endl;
cin>>m;
int c=m;
double running_time[c];
while(c>0)
{
int arr[n];
int x;
for(x=0;x<n;x++)
{
arr[x] = rand();
}
clock_t start = clock();
int pos = biggest(arr,n);
clock_t t_end = clock();
c--;
running_time[c] = 1000.0*(t_end-start)/CLOCKS_PER_SEC;
}
double avg_running_time = calculate(running_time,m);
result.push_back(make_pair(n,avg_running_time));
cout<<"Enter 1 for iteration\nEnter 2 for exit\n";
cin>>choice;
}
for(int x=0;x<result.size();x++)
{
cout<<result[x].first<<" "<<result[x].second<<endl;
}
}
