All categories

3 years ago

Let f(x) = −4x + 7 and g(x) = 10x − 6. Find f(g(x)).

Mathematics

1 answer:

Neporo4naja [7]3 years ago

7 0

F(g(x))= -4(10x-6) + 7

f(g(x))= -40x + 24 +7

f(g(x))= -40x +31

You might be interested in

14) Simplify: -2x(3 - 5x)

harina [27]

Answer:

-6x +10x= 4x

Step-by-step explanation:

-2x(3 - 5x)

-6x +10x= 4x

3 0

3 years ago

A stock-car race lasted 2.07 hours. how many seconds did the race last?

kolezko [41]

$2.07 hr x \frac{60 min}{1 hr} x \frac{60 sec}{1 min} = 7452 sec$

8 0

3 years ago

50 squared equals 2 + 25 squared equals 2 * 5 equals 10 what is wrong

Klio2033 [76]

Convert to an equation:

50^2=2+25^2=2*5=10

Simplify:

2500=625=10=10

What is wrong is that 2500 does not equal 625 which does not equal 10.

7 0

3 years ago

PLEASE ANSWER< WILL GIVE BRAINLY TO BEST ANSWER!?

Mice21 [21]

A as let’s say we have an isosceles triangle two of the sides are the same but one of the sides usually the base us different . Therefore , for this question the sides will both be equal so both 6 and the base 12-different HOPE THIS HELPS (Brainly best answer pleasee )

7 0

3 years ago

Consider a large shipment of 400 refrigerators, of which 40 have defective compressors. If X is the number among 15 randomly sel

Vlad [161]

Answer:

The required probability is 0.94

Step-by-step explanation:

Consider the provided information.

There are 400 refrigerators, of which 40 have defective compressors.

Therefore N = 400 and X = 40

The probability of defective compressors is:

$\frac{40}{400}=0.10$

It is given that If X is the number among 15 randomly selected refrigerators that have defective compressors,

That means n=15

Apply the probability density function.

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

We need to find P(X ≤ 3)

$P(X\leq3) =P(X=0)+P(X=1)+P(X=2)+P(X=3)\\P(X\leq3) =\frac{15!}{15!}(0.1)^0(1-0.1)^{15}+\frac{15!}{14!}(0.1)^1(1-0.1)^{14}+\frac{15!}{13!2!}(0.1)^2(1-0.1)^{13}+\frac{15!}{12!3!}(0.1)^3(1-0.1)^{12}\\$

$P(X\leq3) =0.944444369992\approx 0.94$

Hence, the required probability is 0.94

4 0

3 years ago