Answer: a,c,f (4^3, 8^2, 2^6)
Step-by-step explanation:
1. 12 mph, 24 miles
2. m=4, y=22
3.15/1, $1500
4. x=30 y=60, k cheaper, j cheaper
Given:
Total amount of Mingfa and her sister = $130
If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.
To find:
How much money does Mingfa actually have?
Solution:
Let, Mingfa have $x and her sister has $y initially. Then,
...(i)
If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.
...(ii)
Substitute the value of x from (ii) in (i).
Divide both sides by 4.
Putting
in (i), we get



Therefore, Mingfa have $95.
Answer:
b. 0.25
c. 0.05
d. 0.05
e. 0.25
Step-by-step explanation:
if the waiting time x follows a uniformly distribution from zero to 20, the probability that a passenger waits exactly x minutes P(x) can be calculated as:

Where a and b are the limits of the distribution and x is a value between a and b. Additionally the probability that a passenger waits x minutes or less P(X<x) is equal to:

Then, the probability that a randomly selected passenger will wait:
b. Between 5 and 10 minutes.

c. Exactly 7.5922 minutes

d. Exactly 5 minutes

e. Between 15 and 25 minutes, taking into account that 25 is bigger than 20, the probability that a passenger will wait between 15 and 25 minutes is equal to the probability that a passenger will wait between 15 and 20 minutes. So:

$5125.78. For simple questions like this you can search them on google and find answers very quickly so you dont waste points btw.