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Anna [14]
3 years ago
10

For each minute a race car traveled, the pit crew measured the speed of the car in miles per hour.

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0
I would represent that with a line graph.
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I need help asap with thissssssssssss
ycow [4]

Answer:

D

Step-by-step explanation:

The domain is the x value which in this case would be the hours of training

3 0
2 years ago
Solve using square root method
avanturin [10]
\frac{1}{2}(x+5)^2 + 9 = -15

\frac{(x+5)^2+18}{2} =  \frac{-30}{2}

Cancel out the denominators.

(x+5)² + 18 = -30

(x+5)² = -30 - 18

(x+5)² = -48

The equation is impossible, we have a negative number.

There isn't a number that squared gives a negative number (the square is always positive).

√(x+5)² = +/- √-48

x+5 = +/- √-48

IMPOSSIBLE

You can write the result in imaginary numbers

x+5=+/- 4i√3
6 0
3 years ago
How to write 12,375,003 in expanded form
icang [17]
Twelve million threehundred and seventy five thousand ans three
6 0
3 years ago
there are 4800 plastic spoons in a case there 6 box3s of spoons in each case how many spoons are in each box
Slav-nsk [51]

Sorry if im wrong but i am pretty sure that is 266

3 0
3 years ago
Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
11 months ago
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