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2 years ago

There are 4 blue marbles, 8 red marbles and 5 green marbles. Write a part to whole ratio comparing green marbles.

Mathematics

2 answers:

yuradex [85]2 years ago

7 0

Answer:

5:17 or 5/17

Step-by-step explanation:

fredd [130]2 years ago

4 0

Answer:

5:17

Step-by-step explanation:

there are 17 total marbles and 5 that are green. The part is 5 and the whole is 17.

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Solving right triangles

Sav [38]

<h2>1. Answer:</h2>

A right triangles is a triangle having a 90 degree side. According to the figure, the sides of this triangle are expressed in inches. Therefore, we can find the missing sides and angles as follows:

<u>m∠B:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle B + 51^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle B = 39^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin39^{\circ}}=\frac{9}{sin51^{\circ}} \\ \\ \therefore CA=\frac{9sin39^{\circ}}{sin51^{\circ}} \\ \\ \therefore \boxed{CA=7.3in}$

$\frac{AB}{sin90^{\circ}}=\frac{9}{sin51^{\circ}} \\ \\ \therefore AB=\frac{9sin90^{\circ}}{sin51^{\circ}} \\ \\ \therefore \boxed{AB=11.6in}$

<h2>2. Answer:</h2>

According to the figure, the sides of this triangle are expressed in meters. Therefore, we can find the missing sides and angles as follows:

<u>m∠A:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 53^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle A = 37^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin53^{\circ}}=\frac{5}{sin90^{\circ}} \\ \\ \therefore CA=\frac{5sin53^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CA=4.0m}$

$\frac{CB}{sin37^{\circ}}=\frac{5}{sin90^{\circ}} \\ \\ \therefore CB=\frac{5sin37^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CB=3.0m}$

<h2>3. Answer:</h2>

According to the figure, the sides of this triangle are expressed in miles. Therefore, we can find the missing sides and angles as follows:

<u>m∠B:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 28^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle B = 62^{\circ}}$

We must use the law of sines as follows:

$\frac{CB}{sin28^{\circ}}=\frac{29.3}{sin62^{\circ}} \\ \\ \therefore CB=\frac{29.3sin28^{\circ}}{sin62^{\circ}} \\ \\ \therefore \boxed{CA=15.6mi}$

$\frac{AB}{sin90^{\circ}}=\frac{29.3}{sin62^{\circ}} \\ \\ \therefore AB=\frac{29.3sin90^{\circ}}{sin62^{\circ}} \\ \\ \therefore \boxed{AB=33.2mi}$

<h2>4. Answer:</h2>

According to the figure, the sides of this triangle are expressed in miles. Therefore, we can find the missing sides and angles as follows:

<u>m∠A:</u>

The sum of the three interior angles of any triangle is 180°, therefore:

$m \angle A + 24^{\circ} + 90^{\circ} = 180^{\circ} \\ \\ \boxed{m \angle A = 66^{\circ}}$

We must use the law of sines as follows:

$\frac{CA}{sin66^{\circ}}=\frac{14}{sin90^{\circ}} \\ \\ \therefore CA=\frac{14sin66^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CA=12.8mi}$

$\frac{CB}{sin24^{\circ}}=\frac{14}{sin90^{\circ}} \\ \\ \therefore CB=\frac{14sin24^{\circ}}{sin90^{\circ}} \\ \\ \therefore \boxed{CB=5.7mi}$

8 0

3 years ago

What is the greatest common factor of 39, 42, and 33?<br> HELP PLSSS!!!

stealth61 [152]

Answer:

What is the greatest common factor of 33 and 39?=3

Step-by-step explanation:

We found the factors and prime factorization of 33 and 39. The biggest common factor number is the GCF number. So the greatest common factor 33 and 39 is 3.

6 0

3 years ago

Read 2 more answers

Can someone pleaseee answer this ! make sure that you show work please .

Harman [31]

Answer:

$65 x .20 = 13 ($13 Discount)

65 minus 13 is 52. NEW PRICE IS $52. YOU SAVED $13

7 0

4 years ago

Help please 20 points available for correct answer otherwise I’ll report. Ven diagrams and probability and I’ll put on more poin

Diano4ka-milaya [45]

Answer:

3 should be put in the box in the upper left corner, since it represents the number of students who have neither a cat or a dog.

15 should be put in the box to the left, since that's how many students who have cats.

Same goes for the box to the right, in which 16 should be put, since 16 students have a dog.

And finally, how do we find the number in the middle?

Well, we know that in 25 students, 3 don't have either a cat or dog, so 22 have pets.

However, the total of the people who have dogs and the people who have cats is 15 + 16 = 31 students!

This is because some people have both cats and dogs.

It's pretty simple to find that number, since all you have to do is to subtract 22 from 31, which comes out to 9.

Hence, 9 should be put in the middle box, which represents students who have both a cat and a dog.

Finally, the probability of a student having both a cat and a dog can be found by 9/25 * 100% = 36%.

Step-by-step explanation:

Hope this helped!

3 0

3 years ago

The value of the digit in the hundreths place is how many times as much as the value of the digit in the tenths place. 0.44

Rus_ich [418]

Answer:

Given number = 0.44

Find how many times the value of the hundredths place digit to the value of the tenths place digit.

=> Since this is a decimal number, I believe, the value you mean is tenths and hundredths, not tens and hundreds.

Now, how many times is the value of each digit differs from each other:

The answer is 10 times

=> 4 hundredths x 10 = 4 tenths

=> 0.04 x 10 = 0.4, which is correct

Step-by-step explanation:

8 0

3 years ago