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OLga [1]
2 years ago
8

Help me please!!!!!

Mathematics
2 answers:
g100num [7]2 years ago
7 0

It would be answer choice A (10^5) because there are 5 10s in the problem
STatiana [176]2 years ago
4 0
10^5 it's 5 10's being multipled
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What is 11/2 divided by 3/4
madam [21]

Answer:

2 and 14/15

Step-by-step explanation:

7 0
2 years ago
What is the length of c in inches
crimeas [40]

Answer:

\sqrt{500} inches

Step-by-step explanation:

a^2+b^2=c^2

10^2+20^2=c^2

100+400=c^2

c^2=500

\sqrt{500}

4 0
3 years ago
The width of a rectangular swimming pool is 16ft. The diagonal of the swimming pool is 34 ft. What is the length of the swimming
kobusy [5.1K]
The length of the swimming pool is 30 ft  
5 0
3 years ago
Read 2 more answers
(x,-2) and (-9,1);slope: -3
amid [387]

Answer:

x= -10

Step-by-step explanation:

The equation is y2-y1 over x2 over x1 so

1-(-2) over -9-(x)=3

1+2=3 over -9-(x)

3/-9-x   times -9-x  = 3  times -9-x

3=3(-9-x)

3=-27-3x

3+27=-3x

30= -3x

-10= 3x

hope it helps man!!! :)

ps may i have brainliest so i can level up

6 0
3 years ago
Kara did a survey to determine to study the types of pets that students in her school had. She surveyed 300 students and found t
julsineya [31]

Answer:

(C)81

Step-by-step explanation:

Total Number of Students =300

Percentage who had cats, n(C) = 40%

Percentage who had both cats and dogs , n(C \cap D) = 12%

Percentage who had neither cats nor dogs, n(C \cup D)' =45%

Now:

Universal Set, U = n(C)+n(D)-n(C \cap D)+n(C \cup D)'

100 = 40 + n(D)-12+45\\n(D)=100-73\\$Percentage of those who own dogs =27\%

Therefore:

Number of Students who had dogs

=27% of 300

=81

3 0
3 years ago
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