The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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the answer is A couse divide all 5
Answer:
152
Step-by-step explanation:
484-28=456
456/3=152
For this case the first thing you should do is observe that the diameter of the four semicircles is the same.
Therefore, we can decompose the figure as follows:
1) We draw the diameters of the four semicircles to form a square.
2) We divide the figure into a square and four semicircles
3) The total area is the sum of the area of the square, plus the area of the 4 semicircles.
Answer:
c)as a square and four semicircles
Answer
Step-by-step explanation: example
5/(X+2). + 2/(X+1)
Common denominator. Is both (X+2)(X+1)
So the first fraction needs (X+1) since it already has (X+2) the second fraction needs ( X+2)
5(X+1). / (X+2)((X+1) +. 2/(X+2)/(X+1)
So multiply 5 with X then 5 with 1 and 2 times X and 2 times 2
5x+5 + 2x+4 / (X+2)((X+1)
Answer 7x+9/ (X+2)(X+1)
