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3 years ago

5 - (-7) = 5+ ___ write as addition

Mathematics

2 answers:

polet [3.4K]3 years ago

8 0

Answer

12 is the answer

shtirl [24]3 years ago

4 0

Answer: It’s 7

Step-by-step explanation:

The other person was wrong i just did the question

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Tyler is thinking of a number that is divisible by 2 and by 3. Write another number in which Tyler's number must also be divisib

Mumz [18]

Answer:

Step-by-step explanation:

6 because 6/2=3,6/3=2

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3 years ago

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Oksanka [162]

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3 years ago

Read 2 more answers

What is the side length of the eectagkes

dedylja [7]

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Step-by-step explanation:

1. 5 in and 1/3 in

Here,

$Let\\l=5\\w=\frac{1}{3}\\Area=l*w\\=5*\frac{1}{3}\\=\frac{5}{3}\ in^2$

2. 5 in and 4/3 in

Here,

$l= 5\ in\\w=\frac{4}{3}\ in\\Area=l*w\\=5*\frac{4}{3}\\=\frac{20}{3}\ in^2$

3. 5/2 in and 4/3 in

$let\\l=\frac{5}{2}\\w=\frac{4}{3}\\Area= \frac{5}{2}*\frac{4}{3}\\=\frac{20}{6}=\frac{10}{3}\ in^2$

4. 7/6 in and 6/7 in

Let

$l=\frac{6}{7}\\w=\frac{7}{6}\\Area=l*w\\=\frac{6}{7}*\frac{7}{6}\\=1\ in^2$

Hence,

1. 5 in and 1/3 in: Area = 5/3 in^2

2. 5 in and 4/3 in: Area= 20/3 in^2

3. 5/2 in and 4/3 in: Area=10/3 in^2

4. 7/6 in and 6/7 in: Area = 1 in^2

Keywords: Rectangle, Area

Learn more about rectangles at:

#LearnwithBrainly

8 0

3 years ago

Next, find the length of BC. Place point F at (4,4), and draw BF and FC. Find BF and FC using the coordinates of B, C, and F. Th

hammer [34]

9514 1404 393

Answer:

BC = 5

Step-by-step explanation:

Of course, this geometry program can tell you the length of BC.

If you follow directions, you get a right triangle BCF that has leg lengths 3 and 4. The Pythagorean theorem then tells you the length of hypotenuse BC is ...

BF = 4 -1 = 3

FC = 4 -0 = 4

BC² = BF² +FC²

BC² = 3² +4² = 9 +16 = 25

BC = √25

BC = 5

7 0

3 years ago

True or false? A figure that has opposite sides with equal lengths and equal slopes and diagonals with slopes that are negative

Alex787 [66]

Answer:

False.

Step-by-step explanation:

The diagonals are at right angles ( because of the negative reciprocal slopes)

so it could be a square or a rhombus.

3 0

3 years ago