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Svetradugi [14.3K]
3 years ago
15

Can someone help me plz (-5x^4y^2)^3

Mathematics
1 answer:
yan [13]3 years ago
5 0
(-5x⁴y²)³

To avoid confusion, we can separate each variable and raise it to the 3rd power.

-5³ * (x⁴)³ * (y²)³

-5³ = -5 * -5 * -5 = -125
(x⁴)³ = x⁴*³ = x¹²
(y²)³ = y²*³ = y⁶

<span>(-5x⁴y²)³ = -125x</span>¹²y⁶
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(10v^4 + 30v^3 + 2v^2) / 10v
Zina [86]

Given expression is

\frac{10v^4+30v^3+2v^2}{10v}

Now we need to simplify this expression. We can begin by factoring numerator and denominator if possible.

= \frac{2v^2(5v^2+15v+1)}{10v}

divide numerator and denominator both by 2v

= \frac{v(5v^2+15v+1)}{5}

= \frac{5v^3+15v^2+1v}{5}

Hence final answer is \frac{5v^3+15v^2+1v}{5}

Or you can also keep factored form

\frac{v(5v^2+15v+1)}{5}

3 0
4 years ago
Hey everyone !
zhuklara [117]

Answer:

The measure of the largest angle is 120°

Step-by-step explanation:

<em>Lets explain how to find the measure of an angle from the length of the </em>

<em>sides of the triangle</em>

- We can do that by using the cosine rule

- If the three angles of the triangle are A , B , C, then the side opposite

 to angle A is BC , the side opposite to angle B is AC and the side

 opposite to angle C is AB, So to find measure of angle A use the rule

 cos(A)=\frac{(AB)^{2}+(AC)^{2}-(BC)^{2}}{2(AB)(AC)}

<em>Lets solve the problem</em>

- Assume that the triangle is ABC where AB = 14 cm , BC = 10 cm and

 AC = 6 cm

- We need to find the measure of the largest angle

- The largest angle is opposite to the longest side

∵ The longest side is AB

∴ The largest angle is C

By using the rule above

∴ cos(C)=\frac{(AC)^{2}+(BC)^{2}-(AB)^{2}}{2(AC)(BC)}

∵ AB = 14 cm , BC = 10 cm , AC = 6 cm

∴ cos(C)=\frac{(6)^{2}+(10)^{2}-(14)^{2}}{2(6)(10)}

∴ cos(C)=\frac{36+100-196}{120}

∴ cos(C)=\frac{-60}{120}=-0.5

∴ cos(C) = -0.5 ⇒ that means angle C is obtuse angle

∴ m∠C = cos^{-1}(-0.5)=120

* <em>The measure of the largest angle is 120°</em>

8 0
3 years ago
Read 2 more answers
The right triangle on the right is a scaled copy of the right triangle on the left. Identify the scale factor. Express your answ
Sonja [21]

Answer:

1/3

Step-by-step explanation:

the one on the left is 3 times larger than the one on the right. in other words, the right triangle's dimensions times 1/3 is equal to the left triangle's dimensions.

5 0
3 years ago
RS bisects TU at Q. If TQ=5k-9 and QU=15-x
snow_lady [41]

Answer:

x = 4, TU = 22

Step-by-step explanation:

Given that TS bisects TU at Q , then

TQ = QU , substitute values

5x - 9 = 15 - x ( add x to both sides )

6x - 9 = 15 ( add 9 to both sides )

6x = 24 ( divide both sides by 6 )

x = 4

Thus

TU = 5x - 9 + 15 - x = 4x + 6 = 4(4) + 6 = 16 + 6 = 22

4 0
3 years ago
Solve |y - 2|&lt;10<br><br> Please help
ElenaW [278]

Step-by-step explanation:

y-2<10

y >12

y bigger than 12.

3 0
3 years ago
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