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3 years ago

9

HELP PLEASE

2 answers:

Juliette [100K]3 years ago

8 0

B. 1/3 because it would be 3/9, but you can make the fraction smaller.

viktelen [127]3 years ago

4 0

The answer is 3/9 or 1/3 chance of selecting a pair of white socks

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Un número racional positivo siempre es menor que un número racional negativo

Misha Larkins [42]

Answer:

This sentence is true.

Step-by-step explanation:

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3 years ago

Which is the solution set of the inequality 15y-9<36

m_a_m_a [10]

15y - 9 <36.
Add 9 to each side.

15y- 9 (+9) < 36 + 9.
15y < 45.
y < 3.
Hope it helps! :)

7 0

3 years ago

Read 2 more answers

What is the volume of the prism

Scilla [17]

Hey there :)

We know the volume formula of triangular prism
Volume = base x height of prism
= $\frac{1}{2} (base)(height)(height of prism)$

We are given:
The base = 8 in
The height = 15 in
You do not need the 17 in ( it is there to trick you )
The height of the prism = 10 in

Apply the formula,
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= 600 in³

Your final answer will be the last option

6 0

4 years ago

−1/2(7z+4)+1/5(5z−15)

Tanya [424]

Answer:

Step-by-step explanation:

-7z/2 - 2 + z -3

=-5 - 5z/2

5 0

3 years ago

Let A and B be events with =PA0.7, =PB0.3, and =PA or B0.9. (a) Compute PA and B. (b) Are A and B mutually exclusive? Explain. (

kvasek [131]

Answer:

a) $P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

b) False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

c) False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

Step-by-step explanation:

For this case we have the following probabilities given:

$P(A) = 0.7, P(B) =0.7, P(A \cup B) =0.9$

Part a

We want to calculate the following probability: $P(A \cap B)$

And we can use the total probability rule given by:

$P(A \cup B) = P(A) +P(B) - P(A\cap B)$

And if we solve for $P(A \cap B)$ we got:

$P(A \cap B) = P(A) + P(B) -P(A\cup B)= 0.7+0.3-0.9 = 0.1$

Part b

False

The reason is because we don't satisfy the following relationship:

$P(A\cup B) = P(A) + P(B)$

We have that:

$0.9 \neq 0.3+0.7 =1$

Part c

False

In order to satisfy independence we need to have the following condition:

$P(A \cap B) = P(A) *P(B)$

And for this case we don't satisfy this relation since:

$0.1 \neq 0.7*0.3 = 0.21$

4 0

4 years ago