3 years ago

Plz help!! Write the equation that represents the graph shown.

Mathematics

1 answer:

earnstyle [38]3 years ago

8 0

Y=-4x+2
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PLEASE HELP: <br> Which is a Linear function? Y=x^3 + 1 5/6x=y-4 Y=8x^2. Y=1/5x

azamat

Y=1/5x is a linear function

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4 years ago

Unit 3: Parallel and Perpendicular Lines<br> Homework 5: Slopes of Lines

NISA [10]

Use the option number 5 and draw a parallel and perpendicular line across to make the slope of the lines collapse

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A certain drug is made from only two ingredients: compound A and compound B. There are 2 milliliters of compound A used for ever

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The answer is 435 milliliters

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3 years ago

Please answer it now in two minutes

ololo11 [35]

Answer: t = 22

<u>Step-by-step explanation:</u>

Since GI is a midsegment of ΔHJK, then 2GI = JK

Given: GI = t + 11, JK = t + 44

2(t + 11) = t + 44

2t + 22 = t + 44

t + 22 = 44

t = 22

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4 years ago

Show that ∆ABC is a right triangle if A(0, 0), B(3, 2), and C(–2, 3). Find the slope m1 of AB and the slope m2 of AC and verify

Mariana [72]

First we'll show this is a right triangle by the Pythagorean Theorem:

$A(0,0), B(3,2), C(-2, 3)$

$AB^2=3^2+2^2=13$

$AC^2=(-2)^2+3^2=13$

$BC^2 = (-3 -3)^2 + (3 -2)^2 = 26$

Since $AB^2+AC^2=BC^2$ we have a right triangle, by the (converse to the) Pythagorean Theorem. We also see it's isosceles, AB=AC.

$\textrm{Slope of AB} = m_1 = \dfrac{2 - 0}{3 - 0} = \dfrac 2 3$

$\textrm{Slope of AC} = m_2 = \dfrac{3 - 0}{-2 - 0} = -\dfrac 3 2$

$m_1 m_2 = (\frac 2 3)(-\frac 3 2 ) = -1 \quad\checkmark$

That's the end of the homework but I'll go on a bit.

Another way to show perpendicularity, essentially the same as the other two, is by a zero as the dot product of the sides as vectors, differences between vertices.

Vector AB = B - A = (3,2)

Vector AC = C - A = (-2, 3)

AB · AC = 3(-2) + 2(3) = 0

A zero dot product means

AB ⊥ AC

8 0

3 years ago