Question

What is 3c+2(2c+5)=3 solve What is d-15.6=2d-556.3 solve What is 9b-10=2(3b+4) solve Please help me 20 points

Answer 1

The first excersise you have to apply the distributive property,
Multiply,
$2 \times 2c = 4c$
$2 \times 5 = 10$
Then solve with the new equation

$3c + 4c + 10 = 3$
$c = - 1$
For the second one just try and leave the variable alone,

$d = 571.9$
In the third equation also apply the distributive property, then leave the variable alone,

$9b - 10 = 6b + 8$
$3b = 18$
Then divide,

$b = 6$

Answer 2

Answer:

3c+2(2c+5)=3 c=-1

d-15.6=2d-556.3 d=540.7

9b-10=2(3b+4) b =6

Step-by-step explanation: