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3 years ago

In the expression 12a+5, identify the coefficient

Mathematics

1 answer:

grandymaker [24]3 years ago

7 0

A coefficient is the number placed before the variable
a (the letter) is the variable
12 is the coefficient of a
12

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89.891 to the nearest ten thousands place

Orlov [11]

89.890 Is what I would think it would be. Hope it helped.

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3 years ago

Solve the inequality -7+2x<_1 where x equals an integer. (How do you get the answer?)

TEA [102]

Assuming that the <_ means ≤, we can add 7 to both sides, to get 2x≤8. Dividing both sides by 2, we get x≤4

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3 years ago

Find the area of the bedroom with the shape shown in the figure, in square feet. A) 67 ft2 B) 106 ft2 C) 506 ft2 D) 548 ft2

jek_recluse [69]

Answer:

$\large{ \tt{❃ \: EXPLANATION }}:$

Firstly , See the attached picture! :) I splitted the provided figure into two rectangles i.e namely small rectangle & big rectangle !

$\large{ \tt{❁ \: LET'S \: START}} :$

Find out the area of small rectangle having length of 14 ft & width of 12 ft :

$\large{ \tt{ ↦ AREA\: OF \: SMALL \: RECTANGLE= L \times W = 14 \times 12 = \boxed{ \tt{168 \: {ft}^{2} }}}}$

Find out the area of big rectangle having length of 20 ft and width of 19 ft :

$\large{ \tt{↦AREA \: OF \: BIG \: RECTANGLE = L \times W = 20 \times 19 = \boxed{ \tt{380 \: {ft}^{2} }}}}$

Now , Add the area of small rectangle & area of big rectangle :

$\large{ \tt{☄ \:TOTAL \: AREA = AREA \: OF \: SMALL \: RECTANGLE + AREA \: OF \: BIG \: RECTANGLE}}$

$\large{ \tt{⇢168 \: {ft}^{2} + 380 \: {ft}^{2} }}$

$⇢ \boxed {\boxed{ \large{ \tt{548 \: {ft}^{2} }}}}$

$\large{ \boxed{ \tt{⇝ \: OUR\: FINAL\: ANSWER : \boxed{\underline{ \tt{D. \: 548 \: {ft}^{2} }}}}}}$

✺ WORK HARD! So that tommorrow , your parents can be recognized by your name!

♡Hope I helped! ツ

☼Have a wonderful day / evening !☃

# StayInAndExplore !☂

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

7 0

3 years ago

Read 2 more answers

Suppose that triangle ABC is a right triangle with the right angle at C. Let line segment CD be the perpendicular from point C t

neonofarm [45]

Step-by-step explanation:

Given:

Let triangle ACD is aright angle triangle with right angle at C. A line perpendicular to AB join C.

Therefore we can say that line segment CD divides angle at C into two equal angles.

So in ΔACD and ΔCDB

∠ ACD = ∠DCB

and ∠ADC = ∠BDC = 90°

and CD =CD

∴ we can say that ΔACD and ΔCDB are similar triangles.

∴ Area of ΔACD = $\frac{1}{2}\times base\times height$

= $\frac{1}{2}\times AD\times CD$

Area of ΔCDB = $\frac{1}{2}\times base\times height$

= $\frac{1}{2}\times DB\times CD$

Therefore ratio of the areas of ΔACD and ΔCDB is

i.e. $\frac{\Delta ACD}{\Delta CDB}$ = $\frac{\frac{1}{2}\times AD\times CD}{\frac{1}{2}\times DB\times CD}$

= $\frac{AD}{DB}$

∴ Area of the ratio of $\frac{\Delta ACD}{\Delta CDB}$ = $\frac{AD}{DB}$

Hence proved

7 0

3 years ago

What is the slope of the line that passes through the points (-5,2) and (-7,6)

grigory [225]

Answer:

-2

Step-by-step explanation:

slope is equal to: y2-y1

_______ =

x2-x1

6-2 4

______ = _____ = -2

-7-(-5) -2

5 0

4 years ago