Answer: a. 0.61
b. 0.37
c. 0.63
Step-by-step explanation:
From the question,
P(A) = 0.39 and P(B) = 0.24
P(success) + P( failure) = 1
A) What is the probability that the component does not fail the test?
Since A is the event that the component fails a particular test, the probability that the component does not fail the test will be P(success). This will be:
= 1 - P(A)
= 1 - 0.39
= 0.61
B) What is the probability that a component works perfectly well (i.e., neither displays strain nor fails the test)?
This will be the probability that the component does not fail the test minus the event that the component displays strain but does not actually fail. This will be:
= [1 - P(A)] - P(B)
= 0.61 - 0.24
= 0.37
C) What is the probability that the component either fails or shows strain in the test?
This will simply be:
= 1 - P(probability that a component works perfectly well)
= 1 - 0.37
= 0.63
Answer:
However, that's the length of "c" and you're looking to drag it in. So,o you drag in 10^2+7^2=a^2.
Then, as shown by the first picture attatched, you can drag in the one with "c" and "a" with the five shown.
Step-by-step explanation:
To find "c" the diagonal, as explained, you need to use the theorem twice. You can first use it by finding "a", as you already have "b". To find a, you do 10^2+7^2=a^2, the hypotenuse.
100+49=149.
So, a is root 149.
a^2+b^2=c^2 so
149+25=174
Y should equal -7/2 or -3.5
33 / 84 ( these digits divide by 3 first we get)
11 / 28 ( after this there is no number from which we can divide these numbers again so)
11 / 28 is the final answer
Answer:
(2*3)=6; 60= (2*3)*2*5 (prime factorization)
The numbers in the parenthesis can't be taken out because they are the HCF
So just move the 2 and the 5 on both sides and you'll get two pairs that are (6,30) and (12,30)
