Answer:
- <u><em>The height of the missing rectangle is 0.15</em></u>
Explanation:
The image attached has the mentioned <em>histogram</em>.
Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.
Only the rectangle for the class [3,4] is missing.
The height of each rectangle is the relative frequency of the corresponding class.
The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.
In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.
<u>1. Sum of the known relative frequencies</u>:
- 0.2 + 0.3 + 0.15 + 0.1 + 0.1 = 0.85
<u>2. Missing frequency</u>:
<u>3. Conclusion</u>:
- The height of the missing rectangle is 0.15
<span>B. pie chart graph is characterized by presenting data values as portions of a circle </span>
Answer:
No
Step-by-step explanation:
it doesnt add up to 180 degrees
Answer:
order: 2, 3, 1
Step-by-step explanation:
Reasonableness checks and your knowledge of integers and fractions will help you solve this. The offered questions are intended to help you think this through.
<h3>a.</h3>
For an output of -31, the machine (x -2)² cannot possibly be last. Its output can only be positive.
machine 2, (x-2)², cannot be last
Also, machine 3 cannot be last. For the output to be -31, the input to machine 3 must be -1/31. Neither of the other machines can produce a fraction with the inputs they might receive.
<h3>b.</h3>
For an input of x=0, the machine 1/x cannot possibly be first. 1/0 is undefined.
The other two machines will give the following outputs for an input of 0:
machine 1: 4(0) -32 = -32
machine 2: (0 -2)² = 4
It is unlikely that machine 1 will be first, because the other two machines cannot do anything useful with -32 as an input.
machine 3, 1/x, cannot be first
<h3>c.</h3>
The reasoning of part (a) tells you the last machine must be machine 1. The reasoning of part (b) tells you the first machine cannot be 3, so must be 2. The order of the machines must be ...
- machine 2: (0 -2)² = 4 . . . . . . . using an input of 0
- machine 3: 1/4 = 1/4
- machine 1: 4(1/4) -32 = -31 . . . . desired output
14^a is your answer hope i helped you
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