What is the starting point of creating a argument on triangle congruence?

Jackie has fewer than 20 h to work on her jewelry. It takes her half an hour to make a necklace and an hour to make a bracelet.

aivan3 [116]

Question 1.

(Jackie)

0.5x+y<20

y≥2x

x≥0

8 0

4 years ago

You invested $6,500 in an account that pays 6 percent simple interest. how much more could you have earned over a 10-year period

Klio2033 [76]

6500(1.06^10)-10(6500*.06)+6500=$1240.51

6 0

3 years ago

A fitness center is interested in finding a 90% confidence interval for the mean number of days per week that Americans who are

Blababa [14]

Answer:

A. Normal

B. Between 2.078 and 2.722 visits.

C. About 90 percent of these confidence intervals will contain the true population mean number of visits per week and about 10 percent will not contain the true population mean number of visits per week.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

Question A:

By the Central Limit Theorem, normal.

Question B:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.645.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645\frac{2.9}{\sqrt{219}} = 0.322$

The lower end of the interval is the sample mean subtracted by M. So it is 2.4 - 0.322 = 2.078 visits

The upper end of the interval is the sample mean added to M. So it is 2.4 + 0.322 = 2.722 visits.

Between 2.078 and 2.722 visits.

Question c:

90% confidence level, so 90% will contain the true population mean, 100 - 90 = 10% wont.

About 90 percent of these confidence intervals will contain the true population mean number of visits per week and about 10 percent will not contain the true population mean number of visits per week.

5 0

3 years ago

Construct a right triangle whose legs are in the ratio 3:4. What are the ratios of each leg to the hypotenuse?

Leto [7]

hello

this type of question can be described as a pythagorean triple

i.e they come in 3:4:5

the 3:4 signifies the adjacent to opposite sides

x can be calculated using pythagorean theorem