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3 years ago

9

How do you graph 8a-10=38 but a=6?

1 answer:

kherson [118]3 years ago

7 0

To graph this equation, I am going to change it up so you can understand. a, in this case, is x and 38 would be y(but it is already solved). Therefore the equation is y = 8x - 10. This follows the format y = mx +b.

To graph: Since your x is 6, your y is missing, but since it's already solved it's 38. Your coordinates would (6, 38).

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3 years ago

If AB=BC,AB=4=4x-2,andBC=3x+3,fine the length of AB

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Step-by-step explanation:

First, I'm assuming AB=4=4x-2 was a typo and it's supposed to be AB = 4x - 2

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3 years ago

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Step-by-step explanation:

.

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3 years ago

Let L be the line parametrized by x = 2 + 2t, y = 3t, z = −1 − t. (a) Find a linear equation for the plane that is perpendicular

Elden [556K]

Answer:

Step-by-step explanation:

Given that L is a line parametrized by

$x = 2 + 2t, y = 3t, z = −1 − t$

The plane perpendicular to the line will have normal as this line and hence direction ratios of normal would be coefficient of t in x,y,z

i.e. (2,3,-1)

So equation of the plane would be of the form

$2x+3y-z =K$

Use the fact that the plane passes through (2,0,-1) and hence this point will satisfy this equation.

$2(2)+3(0)-(-1) =K\\K =5$

So equation is

$2x+3y-z =5$

b) Substitute general point of L in the plane to find the intersecting point

$2(2+2t)+3t-(-1-t) =5\\4+8t+1=5\\8t=0\\t=0\\(x,y,z) = (2,0,-1)$

i.e. same point given.

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3 years ago