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son4ous [18]
2 years ago
15

Solve for x. Will mark brainliest

Mathematics
1 answer:
Serjik [45]2 years ago
4 0

Answer:

41) x = 8

Step-by-step explanation:

41)

Arc MN is 100 degrees because it is the double of 50 degrees.

12x+4=100

12x-4=100-4

12x=96

x/12=96/12

x=8

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Order the numbers by value.<br> LEAST to GREATEST<br><br>10<br>√99<br>√75<br>9<br>9.5​
beks73 [17]

Answer:

√75, 9, 9.5, √99, 10

Step-by-step explanation:

that's what I got

4 0
2 years ago
Y=x^2 -9x at x = 4 Find an equation of the tangent an an equation of the normal
Montano1993 [528]

The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:

<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

When <em>x</em> = 4, the function takes on a value of

<em>y</em> = 4² - 9•4 = -20

and the derivative is

d<em>y</em>/d<em>x</em> (4) = 2•4 - 9 = -1

Then use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-20) = -1 (<em>x</em> - 4)

<em>y</em> + 20 = -<em>x</em> + 4

<em>y</em> = -<em>x</em> - 24

The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

<em>y</em> - (-20) = 1 (<em>x</em> - 4)

<em>y</em> + 20 = <em>x</em> - 4

<em>y</em> = <em>x</em> - 24

3 0
3 years ago
HELPPPP PLEASEEEeeeeeee
sergij07 [2.7K]

Answer:

I think it is non proportional

5 0
3 years ago
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What is the approximate area of the shaded sector in the circle shown below?
forsale [732]

Answer:

where is the picture...

6 0
2 years ago
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HELP ASAP, DUE AT 11:59<br><br> g(-5)=
Dovator [93]

Answer:

g(-5) = -6

Step-by-step explanation:

We need to find value of g(-5)

Looking at the graph in figure when g = -5, the value on the graph is -6 as it is highlighted with blue point.

because we have x = -5 so, we will look at graph that passes through x and y when x= -5, so we get y=-6

So, g(-5) = -6

6 0
3 years ago
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