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2 years ago

2. Determine the answer to (-5) + 4 and explain the steps using a number line (5 points)

Mathematics

2 answers:

DiKsa [7]2 years ago

8 0

The answer is -4 because it’s flipped

earnstyle [38]2 years ago

7 0

Answer:

-1

Step-by-step explanation:

-5+4=5-4=1

-1 this is the answer

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Edmond doubled the width of the crate. How do the perimeter and the area of the floor of the new crate compare to those of the o

Mariana [72]

Answer:

The area would be doubled also

The perimeter will be increased in a factor of 1.4

Step-by-step explanation:

Originally the area of new crate = L * B = 1.2 * 0.8 = 0.96 m^2

perimeter is 2(L+ B) = 2(1.2 + 0.8) = 4 m

Now let’s double the width , it becomes 0.8 * 2 = 1.6 m

Area would be 1.6 * 1.2 = 1.92 m^2 which is two times the previous area

The increased perimeter will be 2(1.6 + 1.2) = 5.6 m

This is an increase in factor of 1.4

7 0

2 years ago

What is the answer if x=2? -3x^2+14x-2

KIM [24]

Simple...

you have: x=2 --->>> $-3x^{2} +14x-2$

plug it in-->>>

$-3(2)^{2} +14(2)-2$

=14

Thus, your answer.

5 0

2 years ago

Read 2 more answers

Solve the system: 4x – 3y = -21 X=-y-14

Liula [17]

Answer:

The solution for the system of equations is

x=2,y=−2

Explanation:

4x−3y=14.....equation (1)

y=−3x+4.....equation (2)

Solving by substitution

Substituting equation 2 in equation 1

4x−3⋅(−3x+4)=14

4x+9x−12=14

13x=14+12

13x=26

x=2

Finding y by substituting x in equation 1

4x−3y=14

4⋅2−3y=14

8−3y=14

8−14=3y

3y=−6

y=−2

4 0

2 years ago

Read 2 more answers

50 PoInts for math homework Waxton

Free_Kalibri [48]

Check out the attached photo

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5 months ago

When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected

jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

$N=\frac{12.36}{0.03+0.55^t}$

The amount of deer that were initally in the reserve corresponds to the value of N when t=0

$N=\frac{12.36}{0.33+0.55^0}$

$N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12$

A. Initially, there were 12 deer.

B. $N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380$

B. N(10) corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. $N(15)=\frac{12.36}{0.03+0.55^15}=\frac{12.36}{0.03 + 0.00013}=\frac{12.36}{0.03013}= 410$

C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0

2 years ago