Answer:
I will assume that the term "x+2/2" is meant to be "(x + 2)/2)." Otherwise the equation would read (x/3) = x + 1
Step-by-step explanation:
(x/3) = (x + 2)/2
x = 3*(x+2)/2 [Multiply both sides by 3]
x = (3x + 6)/2
x = (3/2)x + 6/2
x - (3/2)x = 3
-0.5x = 3
x = -6
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Check:
Does (x/3) = (x + 2)/2 for x = -6?
(-6/3) = (-6 + 2)/2
-2 = -4/2
-2 = -2 YES
<h3>
Answer: 37</h3>
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Work Shown:
We have a triangle with sides a,b,c such that
The third side c can be represented by this inequality
b-a < c < b+a
which is a modified form of the triangle inequality theorem.
Plug in the given values to get
b-a < c < b+a
20-17 < c < 20+17
3 < c < 37
The third side length is between 3 and 37; it cannot equal 3, and it cannot equal 37. So we exclude both endpoints.
Of the answer choices, the values {7,20, 12} are in the range 3 < c < 37.
The value c = 37 is not in the range 3 < c < 37 because we can't have the third side equal to either endpoint. Otherwise, we get a straight line instead of a triangle forming.
So that's why 37 is the only possible answer here.
Answer:
93 is your answer.
Step-by-step explanation:
What you want to do is PEMDAS.
<em>3 · 32 + 8 ÷ 2 − (4 + 3)</em>
<em>96 + 8 ÷ 2 - 7</em>
<em>96 + 4 - 7 </em>
<em>100 - 7</em>
93 is your answer.
Answer:
(q,0)
Step-by-step explanation:
See the diagram given.
It is clear from the coordinates of the points given that point C (0,r) lies on the Y-axis and point E (-q,o) lies on the X-axis. Hence, point D must be on the X-axis.
ΔCDE being an isosceles triangle, the origin of the coordinate axes will be on the DE line and it will be at the midpoint of DE.
Therefore, ΔCDE will be symmetric with respect to the Y-axis and the coordinates of point D will be (q,0). (Answer)
