The maximum compression of the spring is 0.276 m
Step-by-step explanation:
First of all, we calculate the spring constant of the spring, by using Hooke's law:
where
F = 10 kN = 10,000 N is the force applied
x = 1.25 cm = 0.0125 m is the corresponding compression of the spring
k is the spring constant
Solving for k,
When the truck impacts with the spring, all the kinetic energy of the truck is converted into elastic potential energy of the spring, so we can write
(1)
where
m is the mass of the truck
v = 2 m/s is the initial speed of the truck
is the spring constant
x is the compression of the spring
The mass of the truck can be found from its weight:
So now we can re-arrange eq.(1) to find the compression, x:
Learn more about kinetic energy:
brainly.com/question/6536722
#LearnwithBrainly
Answer:
Susie rounded to the nearest thousandth.
Step-by-step explanation:
since the 100th place is 0 it would round down to 39,000 when you are rounding to the nearest thousand.
Answer:
evaporates
Step-by-step explanation:
Where is the data? Show a picture if you could.
Answer:
352x^2
Step-by-step explanation:
40\times 1.25x\times 2.20x\times 3.2040×1.25x×2.20x×3.20
(40)1.25x2.20x3.20
+ − . ln > <
× ÷ / log ≥ ≤
( ) logx = %
1 Take out the constants.
(40\times 1.25\times 2.20\times 3.20)xx(40×1.25×2.20×3.20)xx
2 Simplify 40\times 1.2540×1.25 to 5050.
(50\times 2.20\times 3.20)xx(50×2.20×3.20)xx
3 Simplify 50\times 2.2050×2.20 to 110110.
(110\times 3.20)xx(110×3.20)xx
4 Simplify 110\times 3.20110×3.20 to 352352.
352xx352xx
5 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x
a
x
b
=x
a+b
.
352{x}^{2}352x
2
Done
