The answer would be -5x-20+15/10
please can i have a brainliest
Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
Answer:
I want to show you how to do this as well, the formula you are working with is a^2+b^2=c^2
Step-by-step explanation:
1.) 8^2+b^2=12^2
64+b^2=144
subtract 64 from both sides
b^2=80
take the square root of 80 and you get
b= 8.9
if you need more help on this let me know, I am going to list the other answers now because to do it all and show work on here is a lot of typing, all of which I will do if you do not understand the first example. Also the c value can ONLY BE THE HYPOTENUSE VALUE. The hypotenuse is the longest side of the triangle. For example, 12 would be the C value on number one and in number two it would be 15.
2.) 14.5
3.) 10.3
4.) 18.8
5.) 8
6.) 15
